url: http://escribe.com/health/thesilverlist/m63052.html
Re: CS>Measuring very high ppms
From: Reid Harvey
Date: Sun, 5 Oct 2003 13:23:49

  > Dan, Mike, Ode,

  > Thanks for all this, and now I feel I'm on my way.  How depressing, that
  > momentary fear I had only 24ppm!  Dan, I highly appreciate your idea of
  > weighing the annode, but appear to have two two of these, in as much as
  > there's a lot of polarity switching, so I've got to weigh both
  > electrodes.  Some time ago someone suggested weighing precipitate, and
  > I'd thought of doing this after inducing it with light and
  > electromagnetic field, like a fan or whatever.  But this is messy and
  > wastes good CS.

  > Reid

  Reid,

  If you  use a constant current generator to drive the cell,  you can
  use the Faraday equations to tell how much silver was  liberated. In
  your case, most of it forms oxides and hydroxides, which is what you
  are trying to make. The equations are in a previous post.

  Even though  your  volume  of  dw  may  change  slightly  during the
  process, you  can simply measure the final volume and get  the total
  ppm.

  You can  measure  the  ionic portion with  the  Hanna  PWT  when the
  solution cools  to room temperature, and subtract it from  the value
  obtained with the Faraday equations.

  Trem, Frank,  and Ivan have shown the conversion  factor  between uS
  and ppm  is unity over a wide range from 3.9 uS to 27 uS.  Since you
  are not adding any other chemicals such as salt, the  reading should
  hold true  even  though you have a lot of  oxides.  The  PWT ignores
  them.

  You can  download  a  program   called   Mercury  that  will  do the
  calculations for you. Here's two places you can get it:

  
http://www.mirror.ac.uk/collections/hensa-micros/collections/aeres/edsw/d-smath/mrcry209.zip

  http://archives.math.utk.edu/software/msdos/calculus/mrcry209/.html

  Now all you need are the unit conversions. Here is a useful list you
  can copy to a file to use with Mercury:

  Cou  = I * sec         ; total number of Coulombs
  esec = I / 1.60217733e-19; electrons per second
  gm   = k * I * sec     ; Faraday's equation
  isin = esec / sqin     ; ions per sq. in. per sec
  isnm = isin / 6.45e14  ; ions per square nanometer per sec
  k    = 107.868 / 96485 ; Coulombs required per gram of silver
  lt   = 3.785 * gal     ; convert gallons to litres
  lt   = ml / 1000       ; convert millilitres to litres
  mg   = gm * 1000       ; convert grams to milligrams
  ml   = 29.57 * oz      ; convert ounce to milliliters
  phr  = ppm / hrs       ; ppm per hour
  ppm  = mg / lt         ; 1 ppm is 1 milligram per litre
  sec  = hrs * 3600 + mnt * 60      ; convert hours to seconds
  uAin = 1e6 * I / sqin  ; current density in uA per sq in

  Append your  data parameters to the list. Here's the ones I  use for
  Godzilla:

  I    = 1.544e-3       ; current
  ml   = 2000           ; volume of dw
  mnt  = 0              ; minutes
  ppm  = 20
  sqin = 11.5           ; wetted area

  When you solve the equations, you will get a list of values. Here is
  the output list for the above data:

  Cou      = 0.001544*sec
           = +35.7789149701487
  I        = +0.001544000000000000
  sec      = 3600*hrs
           = +23172.8723899927
  esec     = +9.6368858246172E+15
  gm       = 0.0062141627320309*hrs
           = +0.040000000000000  { = +1 / 25 }
  k        = +0.00111797688759911
  isin     = +8.3799007170584E+14
  sqin     = +11.500000000000000    { = +23 / 2 }
  isnm     = +1.29920941349743
  lt       = +2.000000000000000
  gal      = +0.52840158520476   { = +400 / 757 }
  ml       = +2000.0000000000000
  mg       = 6.2141627320309*hrs
           = +40.000000000000
  oz       = +67.6361176868448    { = +200000 / 2957 }
  phr      = 20/hrs
           = +3.1070813660154
  ppm      = +20.000000000000000
  hrs      = +6.4369089972202
  mnt      =  0.0000000000000000
  uAin     = +134.260869565217    { = +3088 / 23 }

  The ppm is the 4th parameter from the bottom.

  Now subtract the ionic portion to obtain the amount of oxide.

  If you  weigh  your  electrodes  carefully  and  keep  track  of the
  calculated values for each run, you will eventually get a measurable
  loss in weight.

  It should  correspond with the total of your  calculations  for each
  run, within normal experimental error.

Best Regards,

Mike Monett


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