--- In [email protected], GameOfDeath2 <[EMAIL PROTECTED]> wrote: > > P(Getting lucky on a Rubik's cube)= > P(Getting lucky|one is on a Rubik's cube)= > [P(Getting lucky)-P(Getting lucky|one is not on a Rubik's cube) *P(One > is not being on a Rubik's cube)]/P(One is on a Rubik's cube) > > at least assuming P(One is on a Rubik's cube)>0.
I don't understand this, but what Tyson meant is simply: 1 / numberOf3x3x3CubeStates Cheers! Stefan ------------------------ Yahoo! Groups Sponsor --------------------~--> Get fast access to your favorite Yahoo! Groups. Make Yahoo! your home page http://us.click.yahoo.com/dpRU5A/wUILAA/yQLSAA/MXMplB/TM --------------------------------------------------------------------~-> Yahoo! Groups Links <*> To visit your group on the web, go to: http://groups.yahoo.com/group/speedsolvingrubikscube/ <*> To unsubscribe from this group, send an email to: [EMAIL PROTECTED] <*> Your use of Yahoo! Groups is subject to: http://docs.yahoo.com/info/terms/
