David:  When you had 76 successes, was your strategy to never switch?
 Or did you actually have some sort of strategy (ie - switch
sometimes, and not switch other times).

~ Bob

--- In [email protected], GameOfDeath2
<[EMAIL PROTECTED]> wrote:
>
> --- In [email protected], Tyson Mao <[EMAIL PROTECTED]> 
> wrote:
> >
> > Yeah, in other words, it's giving a blind man a scrambled cube, 
> having 
> > him twirl it around for a bit, and then saying, "I'm done."  Sorry, 
> > getting "lucky" on a Rubik's Cube wasn't a very good way to phrase 
> it.
> > 
> > Tyson Mao
> > MSC #631
> > California Institute of Technology
> > 
> 
> Now I'm more confused! I must be misunderstanding you because I 
> thought you were talking a probability of c. 0.76 which seems very 
> high for randomly solving.
> 
> > On Dec 30, 2005, at 12:26 PM, Stefan Pochmann wrote:
> > 
> > > --- In [email protected], GameOfDeath2
> > > <[EMAIL PROTECTED]> wrote:
> > >>
> > >> P(Getting lucky on a Rubik's cube)=
> > >> P(Getting lucky|one is on a Rubik's cube)=
> > >> [P(Getting lucky)-P(Getting lucky|one is not on a Rubik's cube)
> > > *P(One
> > >> is not being on a Rubik's cube)]/P(One is on a Rubik's cube)
> > >>
> > >> at least assuming P(One is on a Rubik's cube)>0.
> > >
> > > I don't understand this, but what Tyson meant is simply:
> > >
> > > 1 / numberOf3x3x3CubeStates
> > >
> > > Cheers!
> > > Stefan
> > >
> > >
> > >
> > >
> > >
> > >
> > >
> > >
> > > Yahoo! Groups Links
> > >
> > >
> > >
> > >
> > >
> > >
> >
>







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