--- In [email protected], "Mike Bennett"
<[EMAIL PROTECTED]> wrote:
>
> > No, I won't just explain it, that's not my style of teaching :-)
> >
> > Instead, let me ask you questions: What is the real probability to
> > skip at least one of those two parity problems for the 4x4? Why is
it
> > not 100% like I get for adding 50%+50%? What's the correct way to
> > compute it? Then apply this knowledge to your 4-step LL.
> >
> > Cheers!
> > Stefan
>
> That's enough explanation for me.
>
> Is it 75%? 50% of the time you get one parity, and 50% of the time
> you don't get it, you get the other.
That's correct. Can you write it as a concise formula?
> 7/8 * 31/108 .251
> 5/6 * 51/648 .065
> 26/27 * 9/24 .574
> 11/12 * 7/24 .267
> ------------ ----
> 1.16
> So, dividing 41% by 1.16 we get ~35%.
Hmm, that stuff looks like mystery to me :-)
Where do you get all those numbers like 648 from?
Cheers!
Stefan
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