> No, I won't just explain it, that's not my style of teaching :-)
>
> Instead, let me ask you questions: What is the real probability to
> skip at least one of those two parity problems for the 4x4? Why is it
> not 100% like I get for adding 50%+50%? What's the correct way to
> compute it? Then apply this knowledge to your 4-step LL.
>
> Cheers!
> Stefan
That's enough explanation for me.
Is it 75%? 50% of the time you get one parity, and 50% of the time
you don't get it, you get the other.
7/8 * 31/108 .251
5/6 * 51/648 .065
26/27 * 9/24 .574
11/12 * 7/24 .267
------------ ----
1.16
So, dividing 41% by 1.16 we get ~35%.
Did I do that right? :S
-Mike
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