--- In [email protected], "Craig Bouchard"
<[EMAIL PROTECTED]> wrote:
> but didn't want to memorise all the
> algorithms for the last 2 edges, I'd be able to do it now because of
> my knowledge of 3 cycles and the like.
Perhaps I've misunderstood your proposal:
Surely you /will/ still end up with 2 swapped edges (5x5x5 "wings") in
50% of cases. If so, 3-cycles won't be enough.
Mike
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