Sounds like even with EC heads you'll only be 10' off the wall, and still on
a 2.5/12 slope. Increase area by 30%

Thom McMahon, SET
Firetech, Inc.
2560 Copper Ridge Dr
P.O. Box 882136
Steamboat Springs, CO 80488
Tel:  970-879-7952
Fax: 970-879-7926


-----Original Message-----
From: [EMAIL PROTECTED]
[mailto:[EMAIL PROTECTED] On Behalf Of Russell
Sent: Wednesday, June 04, 2008 5:49 AM
To: [email protected]
Subject: RE: Barrel Ceiling

The ceiling curve is the segment of a circle. The room is 40' wide. The
highest point and center of the segment is the center of the room. The
center and highest point is 4'-6" higher than the lowest point at the walls.
I was a little off on my pitch earlier. At the wall it's 5.5" pitch. Half
way from the wall to the center of the segment is 2.5" and then at the
center it is 0.0" of course.



-----Original Message-----
From: [EMAIL PROTECTED]
[mailto:[EMAIL PROTECTED] On Behalf Of Thom McMahon
Sent: Tuesday, June 03, 2008 6:06 PM
To: [email protected]
Subject: RE: Barrel Ceiling

I would agree, but only if you could have a head located far enough from the
edge of the vault so it was on a slope less than or = to 2/12 then the heads
around the perimeter of the vault would act similar to a "Ceiling Pocket"
with heads in the pocket. (In the barrel) But because this starts at a wall,
it is no ceiling pocket. And I just don't think that you can get far enough
in to have the heads on a slope of less than 2/12. The only way to check
this is to know the true shape of the ceiling. Is it part of a true ARC or
some other curved shape? What is the highest point, maybe you can still get
a reduction in area to offset some of the 30% by using QR.

Thom McMahon, SET
Firetech, Inc.
2560 Copper Ridge Dr
P.O. Box 882136
Steamboat Springs, CO 80488
Tel:  970-879-7952
Fax: 970-879-7926



-----Original Message-----
From: [EMAIL PROTECTED]
[mailto:[EMAIL PROTECTED] On Behalf Of Ron Greenman
Sent: Tuesday, June 03, 2008 3:49 PM
To: [email protected]
Subject: Re: Barrel Ceiling

Thom,

I'm not so sure I agree. if you plot out the degrees between where 3
1/2//12 and 0//12 on a quarter circle you get a pretty shallow arc.
The 3 1/2//12 to 2 1/2//12 portion is a lot like attaching a collar tie to a
45 degree rafter a foot or so above the plate, rocking it all and then
arguing for a 30% increase based on the foot or so section around the edge
that's at 6//12. Since code does not address a solution to either situation
the simple, conservative approach would be yours but I think an average
slope along the entire arc should be the criterion. I didn't calculate this
but I'd bet it's less than 2//12.

On Tue, Jun 3, 2008 at 1:34 PM, Thom McMahon <[EMAIL PROTECTED]>
wrote:
> If you exceed the 2/12 (Flat) ceiling anywhere, increase by 30%
>
> Thom McMahon, SET
> Firetech, Inc.
> 2560 Copper Ridge Dr
> P.O. Box 882136
> Steamboat Springs, CO 80488
> Tel:  970-879-7952
> Fax: 970-879-7926
>
>
>
> -----Original Message-----
> From: [EMAIL PROTECTED]
> [mailto:[EMAIL PROTECTED] On Behalf Of Russell
> Sent: Tuesday, June 03, 2008 10:24 AM
> To: AFSA
> Subject: Barrel Ceiling
>
> I'm looking at a project which has a room about 40 feet wide and has a 
> ceiling which is barrel shaped. It is not a deep barrel but rather a 
> large radius, it starts out at the wall with about a 3/12 pitch and as 
> it nears the apex it, of course, levels out. In trying to apply the 
> rule for design area increase due to sloping ceilings this situation 
> seems not to fit the written text very clearly. Can anyone offer an 
> opinion or point me towards a standard/code I can apply?
>
>
>
> Thanks,
>
> Russell
>
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--
Ron Greenman
at home....
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