Is this tank dedicated for fire protection? Why would you assume it is
empty? Then the water is only available for 1 minute while you empty the
riser pipe. Calculate friction loss through riser pipe down and through
sprinkler riser with an assumed flow entering the tank discharge pipe.
Eleveation and friction loss is what you are calculating.

What about doing a flow test from the base of the riser?

Arthur Tiroly
ATCO Fire Protection Design
Tiroly and Associates
216-621-8899
216-570-7030 Cell
WWW.ATCOfirepro.com


-----Original Message-----
From: [email protected]
[mailto:[email protected]] On Behalf Of Todd Williams
Sent: Wednesday, June 16, 2010 7:17 AM
To: [email protected]
Subject: Re: Gravity Tanks

I appreciate everybody's input. What about this? 
Calculate the flow rate discharging at the bottom of the tank at the
pressure due to the elevation of the water in the tank. I found a website
that apparently will do that,
http://www.efunda.com/formulae/fluids/draining_tank.cfm#calc. 
The static and residual pressures will be close to the same but will
decrease over time with the drop in water elevation. You could even make the
assumption on a residual pressure based on elevation after 1 minute of
discharge and it would be conservative. So now you have a static, residual
and flow at the tank discharge. Then you could run it through the piping
down through the building (in this case) as you would any water supply.





At 10:18 PM 6/15/2010, you wrote:
>I think Ralphy has it right. The empty tank level is the worst case 
>pressure condition and in the big picture the falling tank head is 
>nothing compared to 28 floors of head unless the tank height is a few 
>sizes bigger than King Kong. A surprising calculation to make might be 
>the tank stored gallons divided by the system gpm.
>
>On Jun 15, 2010, at 2:40 PM, Ralphy Henderson wrote:
>
> > Couldn't you also do this:
> >
> > For assumption sake let's say 1st floor is light hazard and we're 
> > anticipating we're going to need 400 gpm. Plot out the static 
> > pressure of the tank (at the empty level) over zero gpm then 
> > calculate our friction losses through the main from the water tank 
> > down to the first floor based upon our anticipated 400 gpm and 
> > subtract that from our static to get our residual pressure. Plot out 
> > the residual pressure over 400 gpm and we now have a standard water 
> > supply curve that can be used to determine other pressures at 
> > available flows.
> >
> > --- On Tue, 6/15/10, Brad <[email protected]> wrote:
> >
> > From: Brad <[email protected]>
> > Subject: RE: Gravity Tanks
> > To: "'Matt Grise'" <[email protected]>, 
> > [email protected]
> > Date: Tuesday, June 15, 2010, 5:44 PM
> >
> > For turbulent (sprinkler) flows, friction loss is proportional to 
> > the square of the velocity
> >
> > -----Original Message-----
> > From: Matt Grise [mailto:[email protected]]
> > Sent: Tuesday, June 15, 2010 12:41 PM
> > To: '[email protected]'; '[email protected]'
> > Subject: RE: Gravity Tanks
> >
> > Don't forget friction in the pipes!
> >
> > Matt Grisé PE*, LEED AP
> > Sales Engineer
> > Alliance Fire Protection
> > *Licensed in KS & MO
> >
> > 913.888.0647 ph
> > 913.888.0618 f
> > 913.927.0222 cell
> > www. AFPsprink.com
> >
> >
> > -----Original Message-----
> > From: [email protected]
> > [mailto:[email protected]] On Behalf Of Brad
> > Sent: Tuesday, June 15, 2010 12:39 PM
> > To: [email protected]; [email protected]
> > Subject: RE: Gravity Tanks
> >
> > i.e., if the water level is 280 feet 'above your head', then h=280 
> > ft, v=134 ft/sec (same as the Law of Falling Bodies- if you were 
> > dropped from 280 ft, you would be going 134 ft/sec when you hit the 
> > ground).
> > ft/sec*ft^2=ft^3/sec. If the flow is coming out of 4" pipe, ft^2=.
> > 09----
> > *134= 12 * 7.48= 90---- * 60= 5400 GPM. As the level 'above your head'
> > drops, so does the velocity, so either use calculus, or call h the 
> > bottom of the tank, like I would have to do. It still seems like 
> > magic to me that by just using feet and seconds, given the rated psi 
> > and rpm ONLY, of a fire pump, I can calculate the diameter of the 
> > impeller (v=2*pi*r*f). It seems like magic bcoz for 15 years I tried 
> > to learn sprinkler calcs after the PEs had simplified it enough for 
> > me by factoring gravity out of the formulas.
> >
> > -----Original Message-----
> > From: Brad [mailto:[email protected]]
> > Sent: Tuesday, June 15, 2010 8:30 AM
> > To: [email protected]
> > Subject: RE: Gravity Tanks
> >
> > mgh=.5mv^2
> > m is the same on both sides so
> > v= sq root 2gh
> > h= v^2/2g
> > first thing is forget about gallons, minutes, and psi- use feet and
> > seconds:
> > ft, ft^2, ft^3, sec, sec^2. ft/sec=(ft^3/sec)/ft^2)
> > g=32.2 ft/sec^2 (if this project is on the earth). 7.48 gal/ft^3.
> > water
> > weighs 62.4 lbs/ft^3.
> >
> > -----Original Message-----
> > From: Todd Williams [mailto:[email protected]]
> > Sent: Tuesday, June 15, 2010 5:11 AM
> > To: [email protected]
> > Subject: Gravity Tanks
> >
> > Was there a thread on calculating flow from a gravity tanks a while 
> > back? I couldn't find it. I have to do a calculation on the first 
> > floor of a building fed from a gravity tank on the 28th floor
> >
> > Todd G. Williams, PE
> > Fire Protection Design/Consulting
> > Stonington, CT
> > 860.535.2080
> > www.fpdc.com
> >
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Todd G. Williams, PE
Fire Protection Design/Consulting
Stonington, CT
860.535.2080
www.fpdc.com

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