Don't try to inject common sense into a good debate. 



David Bohannon 

Fire Sprinkler Plan Review City of Atlanta 

Department of Planning and Community Development 

Office of Buildings 

55 Trinity Avenue 

Suite 3900 

Atlanta, GA 30303 

e-mail: [email protected] 

phone:  404-330-6193 

fax:  404-739-4172 





----- Original Message -----


From: "Vince Sabolik" <[email protected]> 
To: [email protected] 
Sent: Monday, April 16, 2012 2:40:06 PM 
Subject: RE: k   -- WHAT? 

Forum -- 

This was my question, so I'd like to clarify a little. 

OK, yes this IS for full flow testing a backflow 
preventer. It was based on being able to calculate a 
performance to save some pipe size. 

AND yes, I was looking for an approximate K "value" for a 2½" valve. 

IF I had to guess, that would be a value of 149, plus or minus. 

BUT since all hydraulics are pretty much based on 
a 50 degree temperature (back in the 1800's the 
folks that were solving these problems 
standardized on that temperature), how can any of this be "precise" 
when you're not gonna find 50 degree water in a 
fire situation in the first place? 

As far as a K Factor, K Value - whatever - goes, 
I was always taught that the value represented a sprinkler, 
a group of sprinklers, etc. etc. etc.  And as all 
of us know, K= GPM/SQR(P).  The formula that was developed 
originally used an expotential of 1.85 
(logarithm) instead of 2, so the results are off to begin with, but close 
enough for rock n roll. 

Most of us (me) can't do log, so we used square 
root in many, many hand calcs. 

I suppose the advent of computers had impact on 
this, but now we're back to being exact - for 50 degree water 
in a fire area. 

It may vary a little bit from manufacturer to 
manufacturer, but given that extact thing, if a K Factor can represent 
a head, group of heads etc., why couldn't  it 
represent a 2½" valve's performance as well? 




At 01:51 PM 4/16/2012, you wrote: 
>Wasn't it a hose valve for forward flushing of 
>the BFP that was the original question? 
> 
>And don't K factors have to be empirically 
>derived? I once tried to determine the logo 
>sprinkler atop a building wherein I worked in 
>1988, and was told without drilling a hole where 
>the orifice was and pumping a LOT of water thru 
>it, we couldn't determine it via formula. I was 
>talking to folks in Lansdale that I think know a 
>lot about large K factors, even back in the 80's. 
> 
>If I were to try to determine how many 2.5" FHV 
>I needed to flow a certain value, I'd simulate 
>it with a test header. Can't think its much 
>different than the # of FHVs needed per #20, and 
>we've been doing that far longer than we've been using even hand calcs. 
> 
>KISB. Keep It Simple, Brad. This is an imprecise business, deal with it. 
> 
> 
>George L.  Church, Jr., CET 
>Rowe Sprinkler Systems, Inc. 
>PO Box 407, Middleburg, PA 17842 
>877-324-ROWE       570-837-6335 fax 
>[email protected] 
> 
> 
>-----Original Message----- 
>From: [email protected] 
>[mailto:[email protected]] On Behalf Of Brad Casterline 
>Sent: Monday, April 16, 2012 11:37 AM 
>To: [email protected] 
>Subject: RE: k -- WHAT? 
> 
>But since friction head with turbulent 
>(sprinkler) flow is proportional to the velocity 
>squared, and the data from Ron Greenman's link 
>says 'K Value for use in the formula 
>hf=k(v^2/2g)', and the velocity varies as the 
>flow, wouldn't the K Value give us the friction 
>loss 'curve' we are looking for, as opposed to an average over a range? 
> 
>-----Original Message----- 
>From: Roland Huggins [mailto:[email protected]] 
>Sent: Monday, April 16, 2012 10:00 AM 
>To: [email protected] 
>Subject: Re: k -- WHAT? 
> 
>I started to say before getting overly precise 
>(but that horse has left the barn), it might be 
>helpful to keep in mind that the K valve on a 
>sprinkler is NOT a constant at different 
>flows.  It is an AVERAGED result for flows from 7 psi to 100 psi. 
> 
>Roland 
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