[Default] On Tue, 12 Feb 2013 13:48:56 -0800,"Frank Shields"
<[email protected]> wrote:

>I wonder what they consider ?full load? when rating the motor. Must be some 
>torque percentage of the HP value or something

Frank The no load speed of an induction motor is near enough the
supply frequency for a 2 pole motor( double the number of poles and
the synchronous rpm halves), so 60Hz is 60 x 60 rpm or 3600. At this
speed the motor is only drawing enough power from the grid to overcome
frictional losses. The voltage you apply to the motor  is matched by a
back electromotive force, a sort of opposing voltage, that is induced
in the windings by the magnetic  force induced in the rotor. As soon
as you put a load on the motor it slows  and the back emf is reduced
but the applied voltage is the same, the difference between these
voltages  is what drives a current through the motor and produces
power.

The rated power of an induction motor is thus developed when there is
an optimum slip, say about 10% which would give a speed of 3240rpm.

If you reduce the forward voltage below the designed voltage for the
same load the slip would increase beyond 10%, the motor would slow but
the current would not reduce as much, so the heating effect would
increase and ultimately the motor would burn out.


AJH

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