Ron, Stovers,
The standard for pellet fuel is actually 50 RPM turned in a special box. So I
need one for 50 RPM but had hoped I could have it do 60 also for some mixing of
materials to determine uptake of metals. Old research had been done at 60 so I
thought….. But now I am thinking all could be done at 50. And I found a unit
to purchase for ~$ 2500 that’s used for testing pellets in animal feed. Seems
the Pellet Fuel Industry took the method for feed pellets for their specs. I
liked Kevin’s comment that if it goes to fast all the pellets will go stick to
the outside so now I wonder how well animal feed relates to wood pellets and
other materials for direct comparison to show the disintegration rate when
handling. I also plan to experiment using biochar and biochar pellets to see if
it will be a useful measure.
The box is turned for a length of time and the powder formed during the run
measured and product rated. Simple test.
For me this has been a very informative discussion and I thank all.
Frank
From: [email protected] [mailto:[email protected]]
Sent: Tuesday, February 12, 2013 4:58 PM
To: Discussion of biomass cooking stoves; Frank Shields
Subject: Re: [Stoves] Calculating the RPM
Frank: It is not clear why your requirement is for such constant rpm (must
be between 59 and 61 rpm to satisfy some standard??)
Crispin is correct that a synchronous motor can do that with simple gearing -
but your 1/3 hp motor at 1725 rpm is almost certainly an induction motor.
Except for clocks, almost all industrial motors are induction - as Andrew was
describing (they are much cheaper).
With a speed sensor, voltage control, and the right set of gears, you can
probably get the constant 60 rpm you want with your existing induction motor.
I presume such speed controllers are on the market at reasonable cost. It may
be cheaper to buy the synchronous type of motor if you have to maintain a
specified speed. If you get the synchronous motor, your deviation from 60 rpm
will be measured probably in thousandths or millionths of a cycle - not +/- one
cycle. This is courtesy of your local electrical supplier, who gets fined a
lot if the grid frequency is ever off by very much
Ron
(taught a motor course once)
_____
From: "Frank Shields" <[email protected]>
To: "Discussion of biomass cooking stoves" <[email protected]>
Sent: Tuesday, February 12, 2013 2:48:56 PM
Subject: Re: [Stoves] Calculating the RPM
Dear Crispin and Kevin,
I wonder what they consider ‘full load’ when rating the motor. Must be some
torque percentage of the HP value or something?
Way more complicated than I thought. Electronic slippage (?) Interesting along
with calculating the speed based on 60 cycles per sec …..
Thanks
For the info.
Frank
From: Stoves [mailto:[email protected]] On Behalf Of
Crispin Pemberton-Pigott
Sent: Tuesday, February 12, 2013 11:15 AM
To: 'Discussion of biomass cooking stoves'
Subject: Re: [Stoves] Calculating the RPM
Dear Frank
The motor will not slow down under no load if you drop the voltage because it
is a synchronous motor. You would have to change the frequency of the AC to
change the speed.
That said, if it was lowered enough the motor couldn’t ‘keep up’ to the 60
cycle synchronous rotation and would slip, slowing down as a result, however
that slippage is strongly dependent on the load which would be really
inconvenient. Being a square box the speed would actually change 4 times per
rotation as the load alternately came and went.
I suspect that the motor is rated at 1725 RPM under full load not actually ‘all
the time’. Under no load it might be very close to 1800 (60 cycles per second *
60 seconds per minute / 2 sets of windings gives 1800).
As it is geared down so much I suspect the motor will not be working hard at
all. Given that you want about a 30:1 reduction and there is a general rule
that you should not step down more than 7:1 at a time, I suggest you get 2 sets
of 1-1/2” and 8” pulleys in series which will give you 28.4:1.
If your speed is 1725, the shaft will turn at 60.64 under load. That is pretty
close. It might go a tiny bit faster but the pulleys are not all that accurate
anyway so you would have to measure it to know. It is slow enough you can count
while watching.
With such an installation you should use Goodyear belts (the ones that are fan
belts but look like they have big teeth). If you drop the voltage it will only
have to slip a little (magnetically speaking) in order to drop one or two RPM
but it will fluctuate a little during the turn because the box is square.
I have a book here for calculating how much power can be transmitted through
the belt contact angle on the small pulley based on their centre distances, if
it matters. I don’t think it will. Pick a centre distance that matches a
common belt.
Regards
Crispin
Dear Frank
1: Box shape and diameter are VERY important. At "critical speed", for a given
combination of rotational speed and container diameter, centrifugal force will
hold the pellets stationary against the container wall, and there will be zero
tumbling and pellet wear. A machine running at say 95% critical speed will
create very little abrasion, but a machine running at say 60% of critical Speed
will create a great deal of abrasion effect, because of the cascading action.
2: Do you want to turn the drum/container/box for a fixed time, OR a fixed
number of revolutions?
3: One could calculate the required HP, but the simplest and least costly thing
is to try the 1/3 HP motor, and if it does not overheat after say 4 consecutive
tests, it is good for the job. If it does overheat, then you have proven that
you need a bigger motor.
Best wishes,
Kevin
----- Original Message -----
From: Frank Shields <mailto:[email protected]>
To: 'Discussion of biomass cooking stoves'
<mailto:[email protected]>
Sent: Tuesday, February 12, 2013 2:30 PM
Subject: [Stoves] Calculating the RPM
Greetings Stovers,
Building equipment for determining the hardness of pellets and biochar I need
something to turn a 9 kg box at a speed of 60 RPM +/- 1.
I have a 1/3rd HP motor that is rated at 1725 RPM
Fitted with a 2” pulley attached to the motor and going to an 8” pulley gives
me a shaft turning 431 RPM
Then another 2” pulley going to an 8” pulley on another shaft gives me 108 RPM
I plan to adjust the 108 down to 60 using a voltage regulator.
Is this a good plan?
And is there another factor I need to include for the weight of the box I am
turning?
Thanks
Frank
Frank Shields
Control Laboratories, Inc.
42 Hangar Way
Watsonville, CA 95076
(831) 724-5422 tel
(831) 724-3188 fax
www.controllabs.com
_____
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