Sérgio,
I presume it is indeed yourself, not a friend, who has been spurned in love. I 
am sorry
to hear it. But I think shutting yourself in a cave for six months is a rather 
extreme
reaction.
However, the good news is that when you come out, you will be in daylight, 
unless your
watch tells sidereal time. This is because, the 24 hour day includes the time 
it takes
for
the earth to spin on its axis once relative to the fixed stars (about 23 hrs 56 
mins)
plus
the time it takes, on average, for the sun to be again overhead the same 
meridian (about
4 mins).

So, after 182 'days' you would emerge to find it is exactly the same time of 
day as when

you went in, give or take only the correction for the infamous Equation of 
Time. So, you

might find it up to about half an hour out.

But I do hope you will be able to reconsider your plight and find some more 
profitable
way to overcome your grief.

Chris Lusby Taylor
Newbury
England
51.3N 1.4W.


Sérgio Garcia Doret wrote:

> Hi everibody
>
>         A friend of mine, ask me two question and I would like have your 
> assistance:
>
> 1 - Assume the hours equals exactly 1/24th of the earth revolution time and
> suppose a disguster lover choose to retire into a cave, where daylight is
> entirelly shut off for a period of six months to the minute. He carries a
> watch  that works to that standard and it is noon when he say goodbye to
> this ungreatful world. After six months he emerges at what he thinks will
> be again noon , but  since the earth has acomplished a half revolution
> around the sun, the cave opening is opposite relatively to the sun to what
> it was six month earlier and the poor fellow has six hours to wait in the
> darkness to see the sun rise again. What adjustment does his watch need?
>
> 2 - If one considers the earth relatively to the sun, it is indisputable
> that the meridian opposite to the sun that corresponds to midnight is where
> day X  turns X+1 as the planet spins around it's axis. Now if you go
> forwards and backwards relatively to that meridian, where do days X and X+1
> meet?
>
> Thanks in advance
> Sergio
>
> Sergio Doret
> Nova Friburgo, RJ    Brasil
> 22º 18'S    42º 32'W
> http://www.alternex.com.br/~sdoret

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