Sergio,
If I read your time period right (snip below) then it would indeed be
for a sidereal period, i.e., the period for the Earth to go through one
revolution. The solar day is slightly longer, i.e., the Earth turns
slightly more than one revolution to bring the Sun back to the meridian
each day. So, you'll loose the delta between sidereal time and solar
time each day, the average delta over a year is approx. 4mins.
1 - Assume the hours equals exactly 1/24th of the earth revolution time
Best,
-Luke
Sérgio Garcia Doret wrote:
>
> Hi everibody
>
> A friend of mine, ask me two question and I would like have your
> assistance:
>
> 1 - Assume the hours equals exactly 1/24th of the earth revolution time and
> suppose a disguster lover choose to retire into a cave, where daylight is
> entirelly shut off for a period of six months to the minute. He carries a
> watch that works to that standard and it is noon when he say goodbye to
> this ungreatful world. After six months he emerges at what he thinks will
> be again noon , but since the earth has acomplished a half revolution
> around the sun, the cave opening is opposite relatively to the sun to what
> it was six month earlier and the poor fellow has six hours to wait in the
> darkness to see the sun rise again. What adjustment does his watch need?
>
> 2 - If one considers the earth relatively to the sun, it is indisputable
> that the meridian opposite to the sun that corresponds to midnight is where
> day X turns X+1 as the planet spins around it's axis. Now if you go
> forwards and backwards relatively to that meridian, where do days X and X+1
> meet?
>
> Thanks in advance
> Sergio
>
> Sergio Doret
> Nova Friburgo, RJ Brasil
> 22º 18'S 42º 32'W
> http://www.alternex.com.br/~sdoret
