On 1/11/07, Wes Moore <[EMAIL PROTECTED]> wrote:
Taking the data for a unit similar to mine for an example: 30,000btu McQuay with a typical condition 50F entering water temp @ 6.1GPM with return air temp @ 70, requires 2.383 KW to operate the pump. This is 8,221 BTU's input. . The output under these conditions is 31,413 BTU's indicating a COP of 3.86. My system draws from a 2,000 gallon pool connected to a thermal solar system … when the pool is 70 to 80 degrees my COP is around 5. I work in this industry and most of my colleagues refer to this as over unity.
The actual input to this system is somewhere above 31,413 BTUs -- not the 8,221BTUs you indicate -- some input being electrical energy, and some being thermal energy in that 50F entering water. When defining a thermodynamic system, it does not matter what form energy crosses the boundry of the system -- thermal, mecahnical, electrical, it all counts. Perhaps in the heat pump industry they refer to this as over-unity, but to a physicist, just hearing that immediately makes us discount it as nonsense. I can't speak for everyone else, but I don't think the arguement here is about whether heat pumps work, or how they work, but whether the definition over-unity can be applied to them.
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