--- In [email protected], "hubby2debbie" 
<[EMAIL PROTECTED]> wrote:

Example
http://pilat.free.fr/english/svg/parabole_bezier.htm

You search intersections of parabola with canvas. Control point is 
intersection of tangents in this points

Michel

> Hi, my name is Peter, and I just found this group. I want to draw an 
> accurate parabola when I have its equation. The math is no problem 
for 
> me, I just need to know how to find the control point for the 
quadratic 
> curve. Actually, I can figure out the x-coordinate of the point, but 
> I'm not sure how to figure out the y-coordinate. Any help would be 
> appreciated.
> 
> Peter





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