Thanks for link. I've studied that information and am trying to adapt the concept to what I need to do.
In the example, to get the three-dimensional effect,it appears that the box is rotated about 30 degrees clockwise and then about 30 degrees down. To get this effect, I'm going to have to calculate the X and Y end points for each of the lines based on the dimensions of the box being displayed. Anyone here have any ideas as to what sort of formula would do this? Any additional info will be greatly appreciated. Thanks. --- In [email protected], "ddailey" <[EMAIL PROTECTED]> wrote: > > This is not quite so complex as what I think you have in mind, but I > happened to see this very nice little demonstration by Antoine Quint the > other day. > http://www.xml.com/pub/a/2002/01/23/svg/index.html?page=2&x- maxdepth=0 > > It is an SVG recreation of a flash thingy ( Niklas Gustavsson's original SWF > animation,) involving cubes bouncing around onmouseover. > > DD ----- To unsubscribe send a message to: [EMAIL PROTECTED] -or- visit http://groups.yahoo.com/group/svg-developers and click "edit my membership" ---- Yahoo! Groups Links <*> To visit your group on the web, go to: http://groups.yahoo.com/group/svg-developers/ <*> To unsubscribe from this group, send an email to: [EMAIL PROTECTED] <*> Your use of Yahoo! Groups is subject to: http://docs.yahoo.com/info/terms/
