Well, what if you wanted to create a String with one character? There’s no way to differentiate.
> On Jul 7, 2016, at 02:35, 王 黎明 via swift-users [swift-users@swift.org](mailto:swift-users@swift.org) wrote: > In Swift, we must specify the type for Character variables(because there’s no Character literals): let eol: Character = “\n” it's not a big problem, but, Is it the unique case that can’t use type infer? ------------------------------ swift-users mailing list swift-users@swift.org https://lists.swift.org/mailman/listinfo/swift-users -- -Saagar Jha
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