> On Jul 10, 2016, at 11:44 , Saagar Jha via swift-users
> <swift-users@swift.org> wrote:
>
> Well, what if you wanted to create a String with one character? There’s no
> way to differentiate.
That hardly seems like the justification. In that case, you'd specify the type:
let s: String = '\n'
>
> > On Jul 7, 2016, at 02:35, 王 黎明 via swift-users
> > [swift-users@swift.org](mailto:swift-users@swift.org) wrote: >
>
> In Swift, we must specify the type for Character variables(because there’s no
> Character literals):
>
> let eol: Character = “\n”
>
> it's not a big problem, but, Is it the unique case that can’t use type infer?
>
> swift-users mailing list swift-users@swift.org
> https://lists.swift.org/mailman/listinfo/swift-users
>
> --
> -Saagar Jha
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--
Rick Mann
rm...@latencyzero.com
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