In Ruby they have special literals, like so: So this would be an array of chars %c{a b c d e f g}
*___________________________________* *James⎥Head of Trolls* *ja...@supmenow.com <ja...@supmenow.com>⎥supmenow.com <http://supmenow.com>* *Sup* *Runway East * *10 Finsbury Square* *London* * EC2A 1AF * On 11 July 2016 at 05:56, Saagar Jha via swift-users <swift-users@swift.org> wrote: > Yes, but then a similar complaint could be made that I *wanted* a String > this time. The only real way to tell the difference is to use something > like single quotes. > > On Jul 10, 2016, at 14:03, Rick Mann via swift-users < > swift-users@swift.org> wrote: > > > On Jul 10, 2016, at 11:44 , Saagar Jha via swift-users < > swift-users@swift.org> wrote: > > Well, what if you wanted to create a String with one character? There’s no > way to differentiate. > > > That hardly seems like the justification. In that case, you'd specify the > type: > > let s: String = '\n' > > > > On Jul 7, 2016, at 02:35, 王 黎明 via swift-users [swift-users@swift.org]( > mailto:swift-users@swift.org <swift-users@swift.org>) wrote: > > > > In Swift, we must specify the type for Character variables(because there’s > no Character literals): > > let eol: Character = “\n” > > it's not a big problem, but, Is it the unique case that can’t use type > infer? > > swift-users mailing list swift-users@swift.org > https://lists.swift.org/mailman/listinfo/swift-users > > -- > -Saagar Jha > _______________________________________________ > swift-users mailing list > swift-users@swift.org > https://lists.swift.org/mailman/listinfo/swift-users > > > > -- > Rick Mann > rm...@latencyzero.com > > > _______________________________________________ > swift-users mailing list > swift-users@swift.org > https://lists.swift.org/mailman/listinfo/swift-users > > > > _______________________________________________ > swift-users mailing list > swift-users@swift.org > https://lists.swift.org/mailman/listinfo/swift-users > >
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