If only you could write this directly in Swift and have it use accelerate…

-Kenny


> On Nov 18, 2016, at 8:07 PM, Jacob Bandes-Storch via swift-users 
> <swift-users@swift.org> wrote:
> 
> I must have forgotten how matrices work—I think it's actually this direction. 
> And I also lost an m :-)
> 
> <image.png>
> 
> 
> On Fri, Nov 18, 2016 at 7:55 PM, Jacob Bandes-Storch <jtban...@gmail.com> 
> wrote:
> Can't you achieve this with a single vector*matrix multiplication?
> 
> [1/n,  1/n,  ...,  1/n] * A  =  [mean(col 1); mean(col 2); ...; mean(col n)]
> 
> Or in more legible form:
> 
> <image.png>
> 
> Jacob
> 
> On Fri, Nov 18, 2016 at 5:36 AM, Yuma Decaux via swift-users 
> <swift-users@swift.org> wrote:
> Hello everyone,
> 
> Nice to meet y'all, and here's my first question:
> 
> I am currently setting a semantically easy to use accelerate operation 
> extension set for my research.
> 
> I have done all the basic operations, vector to scalar, vector to vector, 
> matrix mult matrix, transpose etc, but would like to know what the best 
> approach might be for getting the mean for a matrix, as I am not sure if the 
> result is what I think it is. In fact, I would like an output of m by 1 from 
> an n by m matrix with means of each column vector.
> 
> The function is:
> func vDSP_meanvD(UnsafePointer<Double>, vDSP_Stride, 
> UnsafeMutablePointer<Double>, vDSP_Length)
> 
> I assume for a vector this is fine since it is 1 dimensional, but for 
> matrices here is my question:
> 
> What is the approach to take?
> 1-Do I slice my matrix into m copies of size n where M_i(n by m) and pass 
> them all through vDSP_meanvD?
> 2- Does the stride argument take care of this, in that if I have stride of n, 
> then the ranges [0:n], [n+1: 2n], [2n+1: 3n] will have their mean and std 
> computed?
> 
> 
> Thanks for any pointer
> 
> Best regards,
> 
> 
> 
> 
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