https://github.com/mattt/Surge
Looks good! -Kenny > On Nov 21, 2016, at 3:47 PM, Howard Lovatt <howard.lov...@gmail.com> wrote: > > Take a look at the Surge library. > > On Tue., 22 Nov. 2016 at 4:24 am, Kenny Leung via swift-users > <swift-users@swift.org> wrote: > If only you could write this directly in Swift and have it use accelerate… > > -Kenny > > > > On Nov 18, 2016, at 8:07 PM, Jacob Bandes-Storch via swift-users > > <swift-users@swift.org> wrote: > > > > I must have forgotten how matrices work—I think it's actually this > > direction. And I also lost an m :-) > > > > <image.png> > > > > > > On Fri, Nov 18, 2016 at 7:55 PM, Jacob Bandes-Storch <jtban...@gmail.com> > > wrote: > > Can't you achieve this with a single vector*matrix multiplication? > > > > [1/n, 1/n, ..., 1/n] * A = [mean(col 1); mean(col 2); ...; mean(col n)] > > > > Or in more legible form: > > > > <image.png> > > > > Jacob > > > > On Fri, Nov 18, 2016 at 5:36 AM, Yuma Decaux via swift-users > > <swift-users@swift.org> wrote: > > Hello everyone, > > > > Nice to meet y'all, and here's my first question: > > > > I am currently setting a semantically easy to use accelerate operation > > extension set for my research. > > > > I have done all the basic operations, vector to scalar, vector to vector, > > matrix mult matrix, transpose etc, but would like to know what the best > > approach might be for getting the mean for a matrix, as I am not sure if > > the result is what I think it is. In fact, I would like an output of m by 1 > > from an n by m matrix with means of each column vector. > > > > The function is: > > func vDSP_meanvD(UnsafePointer<Double>, vDSP_Stride, > > UnsafeMutablePointer<Double>, vDSP_Length) > > > > I assume for a vector this is fine since it is 1 dimensional, but for > > matrices here is my question: > > > > What is the approach to take? > > 1-Do I slice my matrix into m copies of size n where M_i(n by m) and pass > > them all through vDSP_meanvD? > > 2- Does the stride argument take care of this, in that if I have stride of > > n, then the ranges [0:n], [n+1: 2n], [2n+1: 3n] will have their mean and > > std computed? > > > > > > Thanks for any pointer > > > > Best regards, > > > > > > > > > > _______________________________________________ > > swift-users mailing list > > swift-users@swift.org > > https://lists.swift.org/mailman/listinfo/swift-users > > > > > > _______________________________________________ > > swift-users mailing list > > swift-users@swift.org > > https://lists.swift.org/mailman/listinfo/swift-users > > _______________________________________________ > swift-users mailing list > swift-users@swift.org > https://lists.swift.org/mailman/listinfo/swift-users > -- > -- Howard. _______________________________________________ swift-users mailing list swift-users@swift.org https://lists.swift.org/mailman/listinfo/swift-users
