Take a look at the Surge library.

On Tue., 22 Nov. 2016 at 4:24 am, Kenny Leung via swift-users <
swift-users@swift.org> wrote:

> If only you could write this directly in Swift and have it use accelerate…
>
> -Kenny
>
>
> > On Nov 18, 2016, at 8:07 PM, Jacob Bandes-Storch via swift-users <
> swift-users@swift.org> wrote:
> >
> > I must have forgotten how matrices work—I think it's actually this
> direction. And I also lost an m :-)
> >
> > <image.png>
> >
> >
> > On Fri, Nov 18, 2016 at 7:55 PM, Jacob Bandes-Storch <jtban...@gmail.com>
> wrote:
> > Can't you achieve this with a single vector*matrix multiplication?
> >
> > [1/n,  1/n,  ...,  1/n] * A  =  [mean(col 1); mean(col 2); ...; mean(col
> n)]
> >
> > Or in more legible form:
> >
> > <image.png>
> >
> > Jacob
> >
> > On Fri, Nov 18, 2016 at 5:36 AM, Yuma Decaux via swift-users <
> swift-users@swift.org> wrote:
> > Hello everyone,
> >
> > Nice to meet y'all, and here's my first question:
> >
> > I am currently setting a semantically easy to use accelerate operation
> extension set for my research.
> >
> > I have done all the basic operations, vector to scalar, vector to
> vector, matrix mult matrix, transpose etc, but would like to know what the
> best approach might be for getting the mean for a matrix, as I am not sure
> if the result is what I think it is. In fact, I would like an output of m
> by 1 from an n by m matrix with means of each column vector.
> >
> > The function is:
> > func vDSP_meanvD(UnsafePointer<Double>, vDSP_Stride,
> UnsafeMutablePointer<Double>, vDSP_Length)
> >
> > I assume for a vector this is fine since it is 1 dimensional, but for
> matrices here is my question:
> >
> > What is the approach to take?
> > 1-Do I slice my matrix into m copies of size n where M_i(n by m) and
> pass them all through vDSP_meanvD?
> > 2- Does the stride argument take care of this, in that if I have stride
> of n, then the ranges [0:n], [n+1: 2n], [2n+1: 3n] will have their mean and
> std computed?
> >
> >
> > Thanks for any pointer
> >
> > Best regards,
> >
> >
> >
> >
> > _______________________________________________
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> > swift-users@swift.org
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> >
> >
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-- 
-- Howard.
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