> No, no, it is continuous because the limit when x-->0 exists (equals > 0), and the same as a value of function at this point, 0**2/0 (which by > definition is equal 0). > In earlier discussions we decided not to allow solutions of equations that set any denominator to zero even though the limit at that point might exist. I wonder if that should be changed so that if the limit exists and is the same from both directions the solution is returned;
>>> e=(x**2*(1/x - z**2/x)) >>> e.expand() -x*z**2 + x >>> solve(_,x) [0] >>> solve(e,x) [] >>> e.subs(x,0) 0 -- You received this message because you are subscribed to the Google Groups "sympy" group. To post to this group, send email to [email protected]. To unsubscribe from this group, send email to [email protected]. For more options, visit this group at http://groups.google.com/group/sympy?hl=en.
