>From wikipedia:

Finding the roots of a given [quintic] polynomial has been a prominent
mathematical problem.

Solving linear <http://en.wikipedia.org/wiki/Linear_equation>,
quadratic<http://en.wikipedia.org/wiki/Quadratic_equation>,
cubic <http://en.wikipedia.org/wiki/Cubic_equation> and quartic
equations<http://en.wikipedia.org/wiki/Quartic_equation>by
factorization <http://en.wikipedia.org/wiki/Factorization> into
radicals<http://en.wikipedia.org/wiki/Nth_root>is fairly
straightforward, no matter whether the roots are rational or
irrational, real or complex; there are also formulae that yield the
required solutions. However, there is no formula for general quintic
equations over the rationals in terms of radicals; this is known as
the Abel–Ruffini
theorem <http://en.wikipedia.org/wiki/Abel%E2%80%93Ruffini_theorem>, first
published in 1824, which was one of the first applications of group
theory<http://en.wikipedia.org/wiki/Group_theory>in algebra. This
result also holds for equations of higher degrees. An
example quintic whose roots cannot be expressed by radicals is [image: x^5
- x + 1 = 0.] This quintic is in Bring–Jerrard normal
form<http://en.wikipedia.org/wiki/Bring%E2%80%93Jerrard_normal_form>
.

As a practical matter, exact analytic solutions for polynomial equations
are often unnecessary, and so numerical methods such as Laguerre's
method<http://en.wikipedia.org/wiki/Laguerre%27s_method>or the
Jenkins-Traub
method <http://en.wikipedia.org/wiki/Jenkins-Traub_method> are probably the
best way of obtaining solutions to general quintics and higher degree
polynomial equations that arise in practice. However, analytic solutions
are sometimes useful for certain applications, and many mathematicians have
tried to develop them.



Jason
moorepants.info
+01 530-601-9791


On Wed, Jun 5, 2013 at 8:23 AM, Stefan Krastanov <[email protected]
> wrote:

> I checked it with Mathematica. It gives the same answer.
>
>
> On 5 June 2013 16:41, Aaron Meurer <[email protected]> wrote:
>
>> Prasoon recently implemented a complete algorithm for solving
>> quintics, so assuming it is working correctly, this does indeed mean
>> that these solutions cannot be represented by radicals.
>>
>> Aaron Meurer
>>
>> On Wed, Jun 5, 2013 at 9:02 AM, Chris Smith <[email protected]> wrote:
>> >>>> [w.n(3) for w in solve(S('x**5 + x**3 + 1'))]
>> > [-0.838, -0.218 - 1.17*I, -0.218 + 1.17*I, 0.637 - 0.665*I, 0.637 +
>> 0.665*I]
>> >
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