One interesting thing to note here is that *solve('x**5 + x**3 + 1')* shows
solution in terms of RootOf, But when we add decimal in the equation then
it shows *polynomial error*
In [35]: solution = [N(w.n(4)) for w in solve('x**5 + x**3 + 9/2' , 'x')]
In [36]: solution
Out[36]:
[-1.21881103515625,
-0.358932495117188 - 1.43544006347656*I,
-0.358932495117188 + 1.43544006347656*I,
0.968338012695313 - 0.865318298339844*I,
0.968338012695313 + 0.865318298339844*I]
In [37]: solution = [N(w.n(4)) for w in solve('x**5 + x**3 + 1.5' , 'x')]
---------------------------------------------------------------------------
PolynomialError Traceback (most recent call last)
On Wednesday, June 5, 2013 2:46:16 PM UTC+5:30, Abhishek kumawat wrote:
>
> When i solve 'x**5 + x**3 + 1', it shows solution as
> [RootOf(x**5 + x**3 + 1, 0),
> RootOf(x**5 + x**3 + 1, 1),
> RootOf(x**5 + x**3 + 1, 2),
> RootOf(x**5 + x**3 + 1, 3),
> RootOf(x**5 + x**3 + 1, 4)]
>
> How to get solution of this equation using sympy.
> Image of the same is attached
>
>
> <https://lh6.googleusercontent.com/-X6chv6Uv09c/Ua8ByKhGqYI/AAAAAAAAAEo/wLGSedGo9jg/s1600/rootof.png>
>
>
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