If the blue dots are fixed on the board, doesn't the linear bearings remove
all degrees of freedom? I don't see how this thing can move.


Jason
moorepants.info
+01 530-601-9791

On Sat, Jun 11, 2016 at 8:57 AM, <[email protected]> wrote:

> They describe the location of the board (the blue rectangle) in relation
> to its "normal" position by a rotation about an angle of phi and a
> translation of x and y.
>
>
>
> On Saturday, June 11, 2016 at 5:40:26 PM UTC+2, Jason Moore wrote:
>>
>> Where are phi, x, y on the diagram?
>>
>>
>> Jason
>> moorepants.info
>> +01 530-601-9791
>>
>> On Sat, Jun 11, 2016 at 6:35 AM, <[email protected]> wrote:
>>
>>> I guess its hard to get from my description, so i uploaded a drawing to
>>> visualize the physical problem: http://pasteboard.co/1Bvt53hY.png
>>>
>>> Thanks for your interest!
>>>
>>>
>>>
>>> On Saturday, June 11, 2016 at 3:13:52 PM UTC+2, [email protected]
>>> wrote:
>>>>
>>>>
>>>> Physically, the rows of A are three points fixed on a movable board.
>>>>
>>>> These points run freely in three linear bearings which are placed on a
>>>> fixed base.
>>>>
>>>> The linear bearings are described in hesse normal form in the rows of
>>>> matrix C.
>>>>
>>>> The robust motion matrix B is the transformation which transforms
>>>> points on the board to points in the base.
>>>>
>>>> So together my constraint D = (A * B) * C means
>>>> - Transform the points in A from the board to the base: A * B
>>>> - Compute the distance from the linear bearings: * C
>>>> - Claim that the distances are zero and solve for the motion
>>>>
>>>> I am aware that there are some other approaches to tackle this problem,
>>>> but i was not able to get a grip on them such that i could formulate them
>>>> in code.
>>>>
>>>>
>>>>
>>>> On Saturday, June 11, 2016 at 1:50:25 PM UTC+2, brombo wrote:
>>>>>
>>>>> Physically what are all the matrices.  Do A and C also describe
>>>>> rotations.  Please give the actual physics problem as well as the 
>>>>> resulting
>>>>> math.
>>>>>
>>>>> On Sat, Jun 11, 2016 at 6:37 AM, <[email protected]> wrote:
>>>>>
>>>>>> My description was a little compressed, so i had to clean up the code
>>>>>> to match my description again ...
>>>>>> The code is available here: http://pastebin.com/MMW3B88h
>>>>>> I hope its readable for you.
>>>>>>
>>>>>>
>>>>>>
>>>>>> Am Donnerstag, 9. Juni 2016 20:24:35 UTC+2 schrieb Jason Moore:
>>>>>>>
>>>>>>> Can you please share the code so we can see what you are doing?
>>>>>>>
>>>>>>>
>>>>>>> Jason
>>>>>>> moorepants.info
>>>>>>> +01 530-601-9791
>>>>>>>
>>>>>>> On Wed, Jun 8, 2016 at 11:58 PM, <[email protected]> wrote:
>>>>>>>
>>>>>>>> I am trying to solve a system of equations with sympy that arises
>>>>>>>> from a constraint of the form:
>>>>>>>>
>>>>>>>>   (A x B) x C = D
>>>>>>>>
>>>>>>>> where
>>>>>>>>
>>>>>>>> * A, B, C and D are 3x3 matrices
>>>>>>>> * the diagonal of D should be zero
>>>>>>>> * B is a "rigid motion 2D" transformation, with elements cos(phi),
>>>>>>>> +-sin(phi), x and y
>>>>>>>> * A and C are fully filled with (supposedly known) values
>>>>>>>> * I want to solve for phi, x and y
>>>>>>>>
>>>>>>>> This gives me four equations:
>>>>>>>>
>>>>>>>> * one for each diagonal element in D
>>>>>>>> * one additional (quadratic) equation sin^2(phi) + cos^2(phi) = 1
>>>>>>>>
>>>>>>>> When feeding those to equations directly to sympy, this takes some
>>>>>>>> hours and then breaks with an out of memory message.
>>>>>>>>
>>>>>>>> My next approach was to help sympy by guiding the solution step by
>>>>>>>> step (*).
>>>>>>>>
>>>>>>>> * First i took two of the linear equations and let sympy solve for
>>>>>>>> x and y (works great)
>>>>>>>> * Instead of having cos(phi) and sin(phi) in the B matrix, i
>>>>>>>> introduced new symbols cosphi and sinphi
>>>>>>>> * Then i took the resulting expressions for x and y, and solve with
>>>>>>>> the third linear equation for the cosphi element (works too)
>>>>>>>> * Finally i tried to solve the quadratic equation for sinphi by
>>>>>>>> inserting the just gathered cosphi expression
>>>>>>>> * The last step was not feasible without transforming the
>>>>>>>> expression to a polynom in sinphi and by replacing all coefficient
>>>>>>>> expressions by new symbols, then it worked
>>>>>>>>
>>>>>>>> The resulting expressions for x, y and phi (written as python
>>>>>>>> expressions) are about 3 MB (!) of text.
>>>>>>>>
>>>>>>>> This does not seem to be adequate to the problem, and when
>>>>>>>> converting to a theano function i get "maximum recursion depth 
>>>>>>>> exceeded".
>>>>>>>> When i look at the expressions they are very repetitive, so i tried
>>>>>>>> CSE, which brings it down to about 30 KB, but they are still very
>>>>>>>> repetitive and full of patterns.
>>>>>>>>
>>>>>>>> I suspect that the resulting expressions actually just perform some
>>>>>>>> matrix operations, so probably there would be an efficient way to 
>>>>>>>> compute
>>>>>>>> the solution if only one could get back to matrix expressions.
>>>>>>>> I tried to guess what the appropriate matrix operations are, but
>>>>>>>> without success (**). And this feels of course very wrong and 
>>>>>>>> backwards.
>>>>>>>>
>>>>>>>> Is there some obvious approach to such problems that i missed? Is
>>>>>>>> the problem actually that hard?
>>>>>>>>
>>>>>>>> I am aiming for a mostly automated solution process without steps
>>>>>>>> like (*) and (**), because i have a hand full of very similar problems
>>>>>>>> ahead ...
>>>>>>>> Any hint appreciated!
>>>>>>>>
>>>>>>>> --
>>>>>>>> Best regards
>>>>>>>> Janosch
>>>>>>>>
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