On Saturday, January 9, 2021 at 5:57:09 AM UTC-6 [email protected] wrote: > But now I have an another question if the manipulation works in > algebraically robust way, > For example, we have lots of pitfalls of expression tree manipulation that > some simple examples like "x / x" work, > but we soon end up with some more complicated examples like " > exp(x+1)/exp(1)" doesn't work robustly, > and the only way to cope with them are appending > .expand().cancel().together().simplify(), ... to the tail which is pretty > much black-boxed and not robust at all. >
At present the `Equation` class does no extra simplification that `sympy` does not already do. Are you asking for the `Equation` class to automatically apply extra simplification steps? Here is the present behavior of a standard `sympy Expr` and the proposed `Equation` classes for your simple example. >>> expr1 = exp(x+1) >>> expr2 = expr1/exp(x) >>> expr2 exp(-x)*exp(x + 1) >>> eq1 = Eqn(a, expr1) >>> eq2 = eq1/exp(x) >>> eq2 a*exp(-x) = exp(-x)*exp(x + 1) >>> expand(eq2) a*exp(-x) = E >>> expand(expr2) E Thanks for the input. Jonathan -- You received this message because you are subscribed to the Google Groups "sympy" group. To unsubscribe from this group and stop receiving emails from it, send an email to [email protected]. To view this discussion on the web visit https://groups.google.com/d/msgid/sympy/677e7470-1356-4a45-93ca-24e91260d27fn%40googlegroups.com.
