SymPy cannot (currently) reduce for multiple variables. As the draft guide
page
<https://output.circle-artifacts.com/output/job/99b313eb-c111-406f-81e3-22dcf5d7c9fa/artifacts/0/doc/_build/html/guides/solving/solve-system-of-inequalities-algebraically.html>
mentions, to reduce for more than one symbol, try SciPy’s linprog()
<https://docs.scipy.org/doc/scipy/reference/generated/scipy.optimize.linprog.html#scipy.optimize.linprog>.
(If there is no solution, obviously no function will find one.)

Jeremy

On Mon, Aug 15, 2022 at 10:48 PM Chris Smith <[email protected]> wrote:

> Ignore your equality `5*x + 2*y+3*z=5` and see if a solution exists for
> the condition you specify:
>
> >>> LP(
> ... x*2-y-z-5,[x <= 1, y <= 1,z <= 1,x>0,y>0,z>0],[x,y,z])
> (-3, {x: 1, y: 0, z: 0}, _y0 + _y1 + _y2 - 5, [_y0 - _y3 - 2 >= 0, _y1 -
> _y4 + 1 >= 0, _y2 - _y5 + 1 >= 0], {_y0: 2, _y1: 0, _y2: 0, _y3: 0, _y4: 0,
> _y5: 0})
>
> The maximum that 2*x - y - z - 5 can be is -3 but you want it to be
> greater than 0. So there is no solution, is there?
>
> /c
>
> On Monday, August 15, 2022 at 3:30:43 AM UTC-5 [email protected] wrote:
>
>> Hi Chris,
>>
>> many thanks for the link to the stack overflow answer and in particular
>> the PR
>> and also the elegant suggestion on how to address the problem with linear
>> programming.
>>
>> I realized that I oversimplified the example though:
>>
>> The problem I want to solve is a vector equation:
>>
>> f_vec+a*x_vec+b*y_vec+n*s_vec=sh_vec+c*xsh_vec+d*ysh_vec
>>
>> and I am looking for a solution with
>>
>> 0<=a,b,c,d<=1
>>
>> I.e. there is more than one equation which need to be satisfied for the
>> same x
>> and y:
>>
>> print(sympy.solvers.inequalities.reduce_rational_inequalities([[x*5 + y*2
>> +z*3=5,x*2-y-z>5,x <= 1, x >= 0, y <= 1, y >= 0,z <= 1, z >= 0]],
>> [x,y,z]))
>>
>> I see no obvious way to apply your method to a set of multiple equations,
>> but
>> it might due to my lack of experience with linear programming.
>>
>> Thanks again
>> Rainer
>>
>>
>> Am Mittwoch, 10. August 2022, 23:03:29 CEST schrieb Chris Smith:
>> > You can't enter your expressions with `=` to create and Equality. You
>> would
>> > have to reenter as Eq(5*x+2*y,10) or
>> > `parse_expr('5*x+2*y=10',transformations=T[1,9]')` (see
>> > [here](https://stackoverflow.com/a/73307040/1089161)).
>> >
>> > Past that, there is no SymPy function that will solve this, but in
>> > PR https://github.com/sympy/sympy/pull/22389 I added code today that
>> will
>> > do so.
>> >
>> > Your equality will be treated like a function to maximize under the
>> >
>> > constrains that x<=1 and y<=1 (and both are nonnegative):
>> > >>> func = 5*x+2*y-10
>> > >>> cond = [x<=1, y<=1]
>> > >>> LP(func, cond, [x,y])[:2]
>> >
>> > (-3, {x: 1, y: 1})
>> >
>> > So that function has a maximum value of -3 when x and y are 1. Now
>> negate
>> > the function and repeat
>> >
>> > >>> LP(-func, cond, [x,y])[:2]
>> >
>> > (10, {x: 0, y: 0})
>> >
>> > The max of the negated function is 10 when x and y are 0. So the min of
>> the
>> > function is -10. You are interested in the case when the function is 0.
>> > Since the function is linear and has as bounds [-10, -3] which does not
>> > contain 0, it seems to me that this proves there is no solution.
>> >
>> > /c
>> >
>> > On Tuesday, August 9, 2022 at 10:46:55 AM UTC-5 [email protected]
>> wrote:
>> > > Hi Jeremy,
>> > >
>> > > thanks for sharing your link and thanks for compiling the
>> documentation.
>> > > And
>> > > indeed it helped, with the information I could easily fix it:
>> > >
>> > > rd@h370:~/tmp.nobackup$ cat test-sympy.py
>> > > import sympy
>> > >
>> > > x, y, z = sympy.symbols('x y z')
>> > > sympy.init_printing(use_unicode=True)
>> > >
>> > > print(sympy.solvers.inequalities.reduce_rational_inequalities([[x + 2
>> >
>> > > 0]],
>> > > x))
>> > >
>> > >
>> > > print(sympy.solvers.inequalities.reduce_rational_inequalities([[x + 2
>> >
>> > > 0,x <
>> > > 5]], x))
>> > > rd@h370:~/tmp.nobackup$ python3 test-sympy.py
>> > > (-2 < x) & (x < oo)
>> > > (-2 < x) & (x < 5)
>> > > rd@h370:~/tmp.nobackup$
>> > >
>> > > I read through your page and posted some feedback at
>> > >
>> > > https://github.com/sympy/sympy/pull/23768
>> > >
>> > > My real problem is somewhat more complex though:
>> > >
>> > > I want to find out if
>> > >
>> > > f_vec+a*x_vec+b*y_vec+n*s_vec=sh_vec+c*xsh_vec+d*ysh_vec
>> > >
>> > > has a solution with
>> > >
>> > > 0<=a,b,c,d<=1
>> > >
>> > > All quantities with _vec are 3 dimensional vectors. I want to to find
>> out
>> > > if
>> > > for a given set of vectors a solution exists or not.
>> > >
>> > > Extending my testcase in this direction does not work though:
>> > >
>> > > rd@h370:~/tmp.nobackup$ cat test-sympy.py
>> > > import sympy
>> > >
>> > > x, y, z = sympy.symbols('x y z')
>> > > sympy.init_printing(use_unicode=True)
>> > >
>> > > print(sympy.solvers.inequalities.reduce_rational_inequalities([[x + 2
>> >
>> > > 0]],
>> > > x))
>> > >
>> > > print(sympy.solvers.inequalities.reduce_rational_inequalities([[x*5 +
>> y*2
>> > > =
>> > > 10,x <= 1, x >= 0, y <= 1, y >= 0]], x))
>> > > rd@h370:~/tmp.nobackup$ python3 test-sympy.py
>> > > File "/home/rd/tmp.nobackup/test-sympy.py", line 9
>> > > print(sympy.solvers.inequalities.reduce_rational_inequalities([[x*5 +
>> y*2
>> > > = 10,x <= 1, x >= 0, y <= 1, y >= 0]], x))
>> > > ^
>> > > SyntaxError: invalid syntax
>> > > rd@h370:~/tmp.nobackup$
>> > >
>> > > I suspect that reduce_rational_inequalities is the wrong approach
>> here,
>> > > but
>> > > what would the the right functions to use?
>> > >
>> > > Any hint is welcome :-)
>> > >
>> > > Many thanks
>> > > Rainer
>> > >
>> > > PS: Also thanks for hint towards less-verbose function calls. I
>> typically
>> > > write it verbose, since I am not writing Python code too frequently,
>> and
>> > > for
>> > > me the verbose version is something like a documentation, since I see
>> > > where
>> > > the functions come from.
>> > >
>> > > Am Samstag, 6. August 2022, 17:19:45 CEST schrieb Jeremy Monat:
>> > > > Hi Ranier,
>> > > >
>> > > > Here's a way to do it:
>> > > > >>> import sympy
>> > > > >>> x, y, z = sympy.symbols('x y z')
>> > > > >>> sympy.solvers.inequalities.reduce_inequalities([x + 2 > 0, x <
>> 5],
>> > > > >>> x)
>> > > >
>> > > > (-2 < x) & (x < 5)
>> > > >
>> > > > reduce_inequalities is the top-level inequality reducer, which will
>> call
>> > > > other lower-level functions (such as reduce_rational_inequalities)
>> as
>> > > > needed. reduce_inequalities takes a simple list, rather than a
>> nested
>> > >
>> > > list,
>> > >
>> > > > of inequalities.
>> > > >
>> > > > I'm actually drafting a guide page on this topic now; glad to know
>> it's
>> > >
>> > > of
>> > >
>> > > > interest! You can access the draft
>> > > > <
>> > >
>> > >
>> https://output.circle-artifacts.com/output/job/a1f8297d-6be8-4627-9f47-a96
>> > > 9
>> > >
>> > >
>> 709f9293/artifacts/0/doc/_build/html/guides/solving/solve-system-of-inequa
>> > > li>
>> > > > ties-algebraically.html>, and I'd appreciate any feedback (either
>> here
>> > >
>> > > or on
>> > >
>> > > > the pull request <https://github.com/sympy/sympy/pull/23768> on
>> GitHub).
>> > > >
>> > > > Best,
>> > > > Jeremy
>> > > >
>> > > > P.S. If you like, you can use less-verbose function calls by
>> importing
>> > > >
>> > > > reduce_inequalities and symbols from SymPy:
>> > > > >>> from sympy import reduce_inequalities, symbols
>> > > > >>> x, y, z = symbols('x y z')
>> > > > >>> reduce_inequalities([x + 2 > 0, x < 5], x)
>> > > >
>> > > > (-2 < x) & (x < 5)
>> > > >
>> > > > On Sat, Aug 6, 2022 at 3:31 AM 'Rainer Dorsch' via sympy <
>> > > >
>> > > > [email protected]> wrote:
>> > > > > Hi,
>> > > > >
>> > > > > I just started with sympy, and try to understand how to tell
>> sympy,
>> > >
>> > > what I
>> > >
>> > > > > want. I tried
>> > > > > print(sympy.solvers.inequalities.reduce_rational_inequalities([[x
>> + 2
>> > > > > >
>> > > > > 0],[x
>> > > > > < 5]], x))
>> > > > > and expected
>> > > > > (-2 < x) & (x < 5)
>> > > > > but got
>> > > > > (-oo < x) & (x < oo)
>> > > > > Can anybody tell how I can tell sympy that x should satisfy both
>> > > > > inequalities
>> > > > > the same time?
>> > > > > For me it seems sympy rather interprets the set of equations
>> rather as
>> > >
>> > > an
>> > >
>> > > > > "or"
>> > > > > and not an "and"
>> > > > >
>> > > > > Here is the full example
>> > > > >
>> > > > > rd@h370:~/tmp.nobackup$ cat test-sympy.py
>> > > > > import sympy
>> > > > >
>> > > > > x, y, z = sympy.symbols('x y z')
>> > > > > sympy.init_printing(use_unicode=True)
>> > > > >
>> > > > > print(sympy.solvers.inequalities.reduce_rational_inequalities([[x
>> + 2
>> > > > > >
>> > > > > 0]],
>> > > > > x))
>> > > > >
>> > > > >
>> > > > > print(sympy.solvers.inequalities.reduce_rational_inequalities([[x
>> + 2
>> > > > > >
>> > > > > 0],[x
>> > > > > < 5]], x))
>> > > > > rd@h370:~/tmp.nobackup$ python3 test-sympy.py
>> > > > > (-2 < x) & (x < oo)
>> > > > > (-oo < x) & (x < oo)
>> > > > > rd@h370:~/tmp.nobackup$
>> > > > >
>> > > > >
>> > > > > Any hint is welcome.
>> > > > >
>> > > > > Thanks
>> > > > > Rainer
>> > > > >
>> > > > >
>> > > > > --
>> > > > > Rainer Dorsch
>> > > > > http://bokomoko.de/
>> > > > >
>> > > > >
>> > > > > --
>> > > > > You received this message because you are subscribed to the
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>> > >
>> > > Groups
>> > >
>> > > > > "sympy" group.
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>> send
>> > >
>> > > an
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>> > > > > email to [email protected].
>> > > > > To view this discussion on the web visit
>> > > > > https://groups.google.com/d/msgid/sympy/4120287.OZXsGyJSKq%40h370.
>>
>>
>>
>> --
>> Rainer Dorsch
>> http://bokomoko.de/
>>
>>
>> --
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