Thanks Mark,
I was going with the assumption of both being equal value but we all
know what it is to assume.
So thanks for pointing that out..."joe"
=================================
[EMAIL PROTECTED] From:
[EMAIL PROTECTED](Mark�Wentowski) Date: Wed, Jun 30, 2004, 7:00pm
(EDT-1) To: [EMAIL PROTECTED] (ELECTRONICS PROFESSIONALS LIST)
Subject: RE: [Techs] electrolytic caps paralleled = x2mfd or divide by
2mfd Reply�to: [EMAIL PROTECTED] (ELECTRONICS PROFESSIONALS
LIST)
Pardon me for butting in but electrolytics in parallel can simply be
added together and the voltage rating is that of the lowest rated cap.
For instance: A 100ufd/50 volt cap in parallel with a 47ufd/16 volt cap
will give you 147ufd. But the voltage rating is limited to 16 volts. But
if both caps are rated at the same voltage (such as 50V) then the
voltage will remain at 50V and you simply add the two ufd values
together to get the ufd rating.
Mark Wentowski
Perry Hill Electronics
3836 Harrison Rd.
Montgomery AL 36109
phone: (334)279-5622
fax: � (334)273-9050
[EMAIL PROTECTED]
-----Original Message-----
From: [EMAIL PROTECTED]
[mailto:[EMAIL PROTECTED] Behalf Of Bil Green Sent:
Wednesday, June 30, 2004 5:22 PM To: ELECTRONICS PROFESSIONALS LIST
Subject: Re: [Techs] electrolytic caps paralleled = x2mfd or divide by
2mfd
Hi Joe,
Multiply cap x 2 when two caps are paralleled (device by 2 when in
series)
--
Best regards,
��Bil Green
�PC 1000
�Mammoth Lakes, CA 93546
��760-924-1000 � � � � � � � � � � � � �
mailto:[EMAIL PROTECTED]
Wednesday, June 30, 2004, 3:44:30 PM, you wrote:
JT> I know vdc stays the same on electrolytic caps paralleled but mfd =
JT> x2mfd or divide by 2mfd. "joe"
JT> Joes....Electronics
JT> �(Joe:Tech/2004)
JT> [EMAIL PROTECTED]
JT> Fax::509-479-2283
JT>�__________________________________________
JT> Tech Repair CD...order your just $49.00 plus shipping...One year of
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