Hmm, that all looks okay. How many stores are attached to products?

-- 
Pat

On 03/07/2010, at 2:43 AM, Ruki Osa wrote:

> Hi Pat
> 
> SELECT `products`.`id` * 1 + 0 AS `id` , CAST(`products`.`name` AS
> CHAR) AS `name`, CAST(`products`.`id` AS CHAR) AS `id`,
> CAST(`products`.`description` AS CHAR) AS `description`,
> CAST(`products`.`age` AS CHAR) AS `age`, CAST(`products`.`productType`
> AS CHAR) AS `productType`, CAST(`brands`.`name` AS CHAR) AS
> `brandName`, CAST(GROUP_CONCAT(DISTINCT `stores`.`name` SEPARATOR ' ')
> AS CHAR) AS `storeName`, `products`.`id` AS `sphinx_internal_id`,
> 485965105 AS `class_crc`, '485965105' AS `subclass_crcs`, 0 AS
> `sphinx_deleted` FROM `products`    LEFT OUTER JOIN `brands` ON
> `brands`.id = `products`.brand_id   LEFT OUTER JOIN `inventorizations`
> ON (`products`.`id` = `inventorizations`.`product_id`)  LEFT OUTER
> JOIN `stores` ON (`stores`.`id` = `inventorizations`.`store_id`)
> WHERE `products`.`id` >= $start AND `products`.`id` <= $end GROUP BY
> `products`.`id`  ORDER BY NULL
> 
> 
> thx
> 
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