About 4, which is why i can't imagine what i am doing wrong. If you think that 
the query looks right i will go through everything again and check.
thx.
Ruki

> Subject: Re: [ts] Re: has_many through
> From: [email protected]
> Date: Sat, 3 Jul 2010 13:50:53 +1000
> To: [email protected]
> 
> Hmm, that all looks okay. How many stores are attached to products?
> 
> -- 
> Pat
> 
> On 03/07/2010, at 2:43 AM, Ruki Osa wrote:
> 
> > Hi Pat
> > 
> > SELECT `products`.`id` * 1 + 0 AS `id` , CAST(`products`.`name` AS
> > CHAR) AS `name`, CAST(`products`.`id` AS CHAR) AS `id`,
> > CAST(`products`.`description` AS CHAR) AS `description`,
> > CAST(`products`.`age` AS CHAR) AS `age`, CAST(`products`.`productType`
> > AS CHAR) AS `productType`, CAST(`brands`.`name` AS CHAR) AS
> > `brandName`, CAST(GROUP_CONCAT(DISTINCT `stores`.`name` SEPARATOR ' ')
> > AS CHAR) AS `storeName`, `products`.`id` AS `sphinx_internal_id`,
> > 485965105 AS `class_crc`, '485965105' AS `subclass_crcs`, 0 AS
> > `sphinx_deleted` FROM `products`    LEFT OUTER JOIN `brands` ON
> > `brands`.id = `products`.brand_id   LEFT OUTER JOIN `inventorizations`
> > ON (`products`.`id` = `inventorizations`.`product_id`)  LEFT OUTER
> > JOIN `stores` ON (`stores`.`id` = `inventorizations`.`store_id`)
> > WHERE `products`.`id` >= $start AND `products`.`id` <= $end GROUP BY
> > `products`.`id`  ORDER BY NULL
> > 
> > 
> > thx
> > 
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