Yeah, it seems fine... so, can you step us through the data in the stores, and 
the search query you're running where you're expecting results?

-- 
Pat

On 04/07/2010, at 3:38 AM, Ernestine Kuti wrote:

> About 4, which is why i can't imagine what i am doing wrong. If you think 
> that the query looks right i will go through everything again and check.
> 
> thx.
> 
> Ruki
> 
> > Subject: Re: [ts] Re: has_many through
> > From: [email protected]
> > Date: Sat, 3 Jul 2010 13:50:53 +1000
> > To: [email protected]
> > 
> > Hmm, that all looks okay. How many stores are attached to products?
> > 
> > -- 
> > Pat
> > 
> > On 03/07/2010, at 2:43 AM, Ruki Osa wrote:
> > 
> > > Hi Pat
> > > 
> > > SELECT `products`.`id` * 1 + 0 AS `id` , CAST(`products`.`name` AS
> > > CHAR) AS `name`, CAST(`products`.`id` AS CHAR) AS `id`,
> > > CAST(`products`.`description` AS CHAR) AS `description`,
> > > CAST(`products`.`age` AS CHAR) AS `age`, CAST(`products`.`productType`
> > > AS CHAR) AS `productType`, CAST(`brands`.`name` AS CHAR) AS
> > > `brandName`, CAST(GROUP_CONCAT(DISTINCT `stores`.`name` SEPARATOR ' ')
> > > AS CHAR) AS `storeName`, `products`.`id` AS `sphinx_internal_id`,
> > > 485965105 AS `class_crc`, '485965105' AS `subclass_crcs`, 0 AS
> > > `sphinx_deleted` FROM `products` LEFT OUTER JOIN `brands` ON
> > > `brands`.id = `products`.brand_id LEFT OUTER JOIN `inventorizations`
> > > ON (`products`.`id` = `inventorizations`.`product_id`) LEFT OUTER
> > > JOIN `stores` ON (`stores`.`id` = `inventorizations`.`store_id`)
> > > WHERE `products`.`id` >= $start AND `products`.`id` <= $end GROUP BY
> > > `products`.`id` ORDER BY NULL
> > > 
> > > 
> > > thx
> > > 
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