I don't quite understand Marks solution so maybe that one is better, or 
just maybe it is exactly what I'm proposing here: I'd think the easier 
strategy would be to filter *all *tiddlers and then remove the ones that *do 
*have links to them. I believe you've solved the latter in your previous 
efforts with backlinks, so you'd do something like

[all[tiddlers]] -[<allwithlinks>]

(I'm not 100% sure of the "minus" syntax, but it's something like that)

<:-)

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