Jim,
Give a try with this script!

<ul>
<$list filter="[all[tiddlers]!is[system]each[surname]get[surname]]">
<li><$link/>(<$count filter="[all[tiddlers]surname<currentTiddler>]"/>)</li>
</$list>
</ul>
You can also replace <$link/>  with <$text text=<<currentTiddler>>/>


Best wishes
Mohammad


On Sun, Aug 29, 2021 at 6:15 PM Jim <[email protected]> wrote:

> Not OP but in my case, I'd like to generate a list of surnames sorted by
> how many tiddlers share the same surname field.
>
> Output should look similar to this:
>
>
>    - Took (26)
>    - Brandybuck (24)
>    - Baggins (24)
>    - Bolger (22)
>    - Boffin (18)
>    - Gardner (14)
>    - Gamgee (7)
>    - Burrows (7)
>
>
> On Sunday, August 29, 2021 at 9:10:08 AM UTC-4 Soren Bjornstad wrote:
>
>> Can you maybe upload a small wiki with some tiddlers that could serve as
>> an example? It's pretty difficult to go into more depth without any data to
>> try it on.
>>>
>>> teric wikiery would be greatly appreciated...
>>>>>
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