Magnus & Mark,

for my Thunderbolt system I found a very good correlation 
between AMU and dBc/ Hz ( observed on my system using 
the ThunderboltMonitor watching over long time stable satellite signals )
when I use the Formula: C/N0(dBHz) = 20 log(AMU) + 23.5.

73,
Arnold



On Sat, 13 Feb 2010 18:12:52 +0100, Magnus Danielson wrote:

>Mark Sims wrote:
>> The data was collected in 0.1 dB / AMU steps.  There was a lot of noise in 
>> the raw data (maybe +/- 1 dB or AMU),  but the general trend of the curve 
>> was quite distinct.   I smoothed it out by hand and filled in a few (maybe 
>> 15) of the missing steps that had no signal.  
>> 
>> The 0.1 resolution of the raw data causes the piecewise linear steps in the 
>> data.  I was going to run a smoothing filter over it,  but the curve is 
>> pretty good as-is (especially considering how it was generated).
>> 
>> Heather now uses a table lookup from 0.0 to 25.5 AMU with a linear 
>> approximation over 25.5 AMU to convert AMU values to dBc values when drawing 
>> the signal level map if the receiver is in AMU mode.  The plots collected in 
>> AMU mode and dBc mode are virtually indistinguishable (within the normal 
>> variation seen between two different runs in dBc mode).                      
>>                     

>My current speculation is this:

>It looks like the AMU unit is normalized and biased such that AMU value 
>0.0 is a reasonable border limit of 20 dBc.

>Thus, from the correlated amplitude A I think the AMU is calculated like 
>this:

>AMU = A/A_norm - A_bias

>A_norm scales linearly with sample-rate of digital sampling.
>A_bias adjusts such that A relating to 20 dBc gives the AMU of 0.0.

>The dBc calculation is more straightforward:

>dBc = 20*log(A/A_norm) + dB_offset

>A_bias of 0.6 to 0.7 and dB_offset of 22.6 isn't too far off.

>Cheers,
>Magnus

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