Brian Kirby wrote:
20 log(base10) (diameter in meters) + 20log(frequency in ghz) +17.8 = dbi
That assumes some nominal efficiency? I'll have to remember that one.. 17.8It's like the 32.44 dB for free space loss between isotropes 1 km apart at 1 MHz
(+20log10(dist in km) + 20log10(freq in MHz)) _______________________________________________ time-nuts mailing list -- [email protected] To unsubscribe, go to https://www.febo.com/cgi-bin/mailman/listinfo/time-nuts and follow the instructions there.
