If I understand you correctly, then I did not have things setup symetrically. Now I have a tee on each of the A and B inputs. The unused port on the B tee has a 50 Ohm terminator. Is this what you mean?
With the above setup, using the shortest cable I have gives me 1.5 ns. Adding the longer cable to the shorter, using a F-F BNC coupler gives me 21 ns, for a difference of 19.5 ns. The readings are bouncing around a bit, so these numbers aren't exact. Using the 19.5 ns figure and a 66% VOP, I get 3.86 M, which is much closer to the measured length. If I use the calculated length vs the measured length, I get a VOP = 65%. Pretty close to the specified 66%. Thanks to everyone for the help. Any more hints or discussion are always appreciated. Joe Gray W5JG On Sat, Apr 2, 2011 at 8:55 PM, Hal Murray <[email protected]> wrote: > > You want the difference in path lengths. Is there an asymmetry in the setup? > If so, count the BNC connectors that don't have a match on the other path. > > If you have input-Tee-coax-Tee-terminator, then the difference is the coax > plus half of each Tee. That is you want to measure the length from center of > Tee to center of Tee. _______________________________________________ time-nuts mailing list -- [email protected] To unsubscribe, go to https://www.febo.com/cgi-bin/mailman/listinfo/time-nuts and follow the instructions there.
