If you rephrase the question, it becomes easier: what is the drive impedance I need to use to inject a signal at this point without getting reflection? 25 ohms because the two lines are in parallel at that point.
Now, however, signals coming from the other lines will not see a matched impedance when they get there and those will get reflected. That's why you don't see that done very often in RF/microwave circuits. Didier KO4BB Sent from my BlackBerry Wireless thingy while I do other things... -----Original Message----- From: Don Otknow <[email protected]> Sender: [email protected] Date: Wed, 6 Apr 2011 11:00:01 To: <[email protected]> Reply-To: Discussion of precise time and frequency measurement <[email protected]> Subject: [time-nuts] Transmission line question Hello, If I have a pin with two 50 ohm lines leading in opposite directions from its land (let's say they are arbitrarily long so as to truly look like 50 ohm lines), what is the effective impedance that the pin sees? Thanks, Donald _______________________________________________ time-nuts mailing list -- [email protected] To unsubscribe, go to https://www.febo.com/cgi-bin/mailman/listinfo/time-nuts and follow the instructions there. _______________________________________________ time-nuts mailing list -- [email protected] To unsubscribe, go to https://www.febo.com/cgi-bin/mailman/listinfo/time-nuts and follow the instructions there.
