Unless it took hours for the light to come out of the star compared to the neutrinos, being at a great distance tends to make the flight time the dominant factor and swamp out small differences due to peculiarities at the point of emission.
Didier KO4BB Sent from my BlackBerry Wireless thingy while I do other things... -----Original Message----- From: "Tom Van Baak" <[email protected]> Sender: [email protected] Date: Mon, 24 Oct 2011 21:38:54 To: Discussion of precise time and frequency measurement<[email protected]> Reply-To: Tom Van Baak <[email protected]>, Discussion of precise time and frequency measurement <[email protected]> Subject: Re: [time-nuts] Neutrino timing > Think big. The experiment has been done over 168,000 light years. > http://en.wikipedia.org/wiki/Supernova_1987A > > The neutrinos got here 3 hours before the light. (Empty space isn't really > empty. The dielectric constant slows the light down a tiny tiny bit.) Hal, Ah, you're assuming the neutrinos came out of the supernova at the same time as the light. I've read that this is not the case. By their nature neutrinos can make it out of that explosion immediately but it takes a while for the light or other particles to migrate their way out from the core. In which case you would expect to see the neutrinos first. This applies to time interval measurement too. The best way to measure interval is use two equivalent detectors; one near and one far, but both away from the source. That way you get two fair in-flight measurements. Using some implied internal trigger and just one far detector may give misleading results. /tvb _______________________________________________ time-nuts mailing list -- [email protected] To unsubscribe, go to https://www.febo.com/cgi-bin/mailman/listinfo/time-nuts and follow the instructions there. _______________________________________________ time-nuts mailing list -- [email protected] To unsubscribe, go to https://www.febo.com/cgi-bin/mailman/listinfo/time-nuts and follow the instructions there.
