Hello Liam,
I've inserted into the web.xml file these lines:
<servlet-mapping>
<servlet-name>Tiparire</servlet-name>
<url-pattern>Tiparire.pdf</url-pattern>
</servlet-mapping>
<servlet>
<servlet-name>Tiparire</servlet-name>
<servlet-class>Tiparire</servlet-class>
</servlet>
Tiparire.class is not part of any package.
Tomcat starts ok, but, when i'm trying to access the location
"servlet/Tiparire.pdf", it says:
"The requested resource (/servlet/Tiparire.pdf) is not
available"
Where is the problem ?
Alex.
Friday, June 21, 2002, 11:56:32 AM, you wrote:
LM> You might need to declare the servlet from within a servlet element like
LM> this as well:
LM> |<servlet-mapping>
LM> <servlet-name>Tiparire</servlet-name>
LM> <url-pattern>Tiparire.pdf</url-pattern>
LM> </servlet-mapping>
LM> <servlet>
LM> <servlet-name>Tiparire</servlet-name>
LM> <servlet-class>Tiparire</servlet-class>
LM> </servlet>
LM> |
LM> servlet-class is actually the fully qualified class name (with package
LM> name etc), just in case it's part of a package.
LM> Liam Morley
LM> Alex wrote:
>>Hello Ralph,
>>
>> I've modified web.xml from ROOT\WEB-INF, and i've added
>> something like this:
>> <servlet-mapping>
>> <servlet-name>Tiparire</servlet-name>
>> <url-pattern>Tiparire.pdf</url-pattern>
>> </servlet-mapping>
>> My servlet is called Tiparire.class and is located into
>> ROOT\WEB-INF\classes
>> But, when i start tomcat, it says:
>> ERROR reading java.io.ByteArrayInputStream@4e280c
>> At Line 11 /web-app/servlet-mapping/
>> What is wrong ?
>>
>> Alex.
>>
>>Friday, June 21, 2002, 11:01:10 AM, you wrote:
>>
>>RE> It's possible to configure tomcat to let you request
>>RE> /servlet/Tiparire/text.pdf and to get /servlet/Tiparire
>>RE> executed. I haven't tried by now to do something like
>>RE> that so can't give you much more help.
>>
>>RE> Maybe something like this should do the trick:
>>
>>RE> <servlet-mapping>
>>RE> <servlet-name>Tiparire</servlet-name>
>>RE> <url-pattern>*.pdf</url-pattern>
>>RE> </servlet-mapping>
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