Hi Matt,
SHACL does not perform any sort of inferencing by default, and there is
no special handling of reified triples. You'd need to pre-process the
input graph, e.g. with a SPARQL CONSTRUCT, to turn the reified triples
into "real" triples.
Holger
On 7/12/2016 2:19, Matt Johnson wrote:
Hello,
Do SHACL property constraints for a given shape/class extend to
reified statements where the subject of the statement is a SHACL instance?
For example, in the following, there are 2 people defined and a
reified statement saying that inst:person-1 ex:knows inst:person-2.
If there is closed shape for type 'Person' that does not provide a
property constraint for 'ex:knows', should I expect a failure? If
not, why?
Thank you!
Matt
inst:person-1
rdf:type ex:Person ;
.
inst:person-2
rdf:type ex:Person ;
.
inst:statement-1
rdf:type rdf:Statement ;
rdf:subject inst:person-1 ;
rdf:predicate ex:knows ;
rdf:object inst:person-2 ;
.
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