Thank you for the confirmation.

On Tuesday, December 6, 2016 at 4:57:54 PM UTC-5, Holger Knublauch wrote:
>
> Hi Matt,
>
> SHACL does not perform any sort of inferencing by default, and there is no 
> special handling of reified triples. You'd need to pre-process the input 
> graph, e.g. with a SPARQL CONSTRUCT, to turn the reified triples into 
> "real" triples.
>
> Holger
>
>
>
> On 7/12/2016 2:19, Matt Johnson wrote:
>
> Hello,
>
> Do SHACL property constraints for a given shape/class extend to reified 
> statements where the subject of the statement is a SHACL instance?
>
> For example, in the following, there are 2 people defined and a reified 
> statement saying that inst:person-1 ex:knows inst:person-2.
>
> If there is closed shape for type 'Person' that does not provide a 
> property constraint for 'ex:knows', should I expect a failure?  If not, why?
>
> Thank you!
>
> Matt
>
> inst:person-1
>   rdf:type ex:Person ;
> .
>
> inst:person-2
>  rdf:type ex:Person ;
> .
>
> inst:statement-1 
>   rdf:type rdf:Statement ;
>   rdf:subject inst:person-1 ;
>   rdf:predicate ex:knows ;
>   rdf:object inst:person-2 ;
> .
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