Hello There,
This problem isn't so simple as it looks in the title/subject of this email.
I am doing a tutorial on Python, and there is a script named password.py:
password = "foobar"
while password != "unicorn":
password = raw_input("Password: ")
print "Welcome in"
The question says "Modify the password guessing program to keep track
of how many times the user has entered the password wrong. If it is
more than 3 times, print “That must have been complicated.”
So I did, I did it in two ways.
Case I:
password = "foobar"
attempt = 0
while password != "unicorn":
password = raw_input("Password: ")
attempt = attempt + 1
if attempt == 3:
print "That must have been complicated.."
print "Welcome in.."
# This script does the half of work. This prints that statement after
three attempts but lets you enter password more time.
Case II:
password = "foobar"
attempt = 0
while password != "unicorn":
password = raw_input("Password: ")
attempt = attempt + 1
if attempt == 3:
print "That must have been complicated.."
break
print "Welcome in.."
# This script performs better than first one, but the problem is it
welcomes you even if you haven't entered the password correct.
Please tell, what can I do?
_______________________________________________
Tutor maillist - Tutor@python.org
To unsubscribe or change subscription options:
http://mail.python.org/mailman/listinfo/tutor
