On 17/07/2012 16:28, Paul McNally wrote:
Date: Tue, 17 Jul 2012 11:23:07 -0400
From: [email protected]
To: [email protected]
CC: [email protected]
Subject: Re: [Tutor] How to print something just after 3 attempts?
On Tue, Jul 17, 2012 at 11:10 AM, Santosh Kumar <[email protected]> wrote:
Hello There,
This problem isn't so simple as it looks in the title/subject of this email.
I am doing a tutorial on Python, and there is a script named password.py:
password = "foobar"
while password != "unicorn":
password = raw_input("Password: ")
print "Welcome in"
The question says "Modify the password guessing program to keep track
of how many times the user has entered the password wrong. If it is
more than 3 times, print “That must have been complicated.”
So I did, I did it in two ways.
Case I:
password = "foobar"
attempt = 0
while password != "unicorn":
password = raw_input("Password: ")
attempt = attempt + 1
if attempt == 3:
print "That must have been complicated.."
print "Welcome in.."
# This script does the half of work. This prints that statement after
three attempts but lets you enter password more time.
Case II:
password = "foobar"
attempt = 0
while password != "unicorn":
password = raw_input("Password: ")
attempt = attempt + 1
if attempt == 3:
print "That must have been complicated.."
break
print "Welcome in.."
move the print "Welcome under break:
break
print "Welcome..."
# This script performs better than first one, but the problem is it
welcomes you even if you haven't entered the password correct.
Please tell, what can I do?
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Joel Goldstick
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I was able to get it working like this...
password = "foobar"
attempt = 0
while (password != "unicorn") and (attempt <= 3):
Please we're talking Python here not C so strip out those unneeded
parenthesis.
password = input("Password: ")
attempt = attempt + 1
if attempt == 3:
print ("That must have been complicated..")
break
if (password == "unicorn"):
ditto.
print ("Welcome in..")
Not sure if it helps.
- Paul
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Cheers.
Mark Lawrence.
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