> Date: Tue, 17 Jul 2012 11:23:07 -0400
> From: joel.goldst...@gmail.com
> To: sntshkm...@gmail.com
> CC: tutor@python.org
> Subject: Re: [Tutor] How to print something just after 3 attempts?
>
> On Tue, Jul 17, 2012 at 11:10 AM, Santosh Kumar <sntshkm...@gmail.com> wrote:
> > Hello There,
> >
> > This problem isn't so simple as it looks in the title/subject of this email.
> >
> > I am doing a tutorial on Python, and there is a script named password.py:
> >
> > password = "foobar"
> >
> > while password != "unicorn":
> > password = raw_input("Password: ")
> > print "Welcome in"
> >
> >
> > The question says "Modify the password guessing program to keep track
> > of how many times the user has entered the password wrong. If it is
> > more than 3 times, print “That must have been complicated.”
> >
> > So I did, I did it in two ways.
> > Case I:
> > password = "foobar"
> > attempt = 0
> > while password != "unicorn":
> > password = raw_input("Password: ")
> > attempt = attempt + 1
> > if attempt == 3:
> > print "That must have been complicated.."
> >
> > print "Welcome in.."
> > # This script does the half of work. This prints that statement after
> > three attempts but lets you enter password more time.
> >
> >
> > Case II:
> > password = "foobar"
> > attempt = 0
> > while password != "unicorn":
> > password = raw_input("Password: ")
> > attempt = attempt + 1
> > if attempt == 3:
> > print "That must have been complicated.."
> > break
> > print "Welcome in.."
> move the print "Welcome under break:
> break
> print "Welcome..."
>
> > # This script performs better than first one, but the problem is it
> > welcomes you even if you haven't entered the password correct.
> >
> > Please tell, what can I do?
> > _______________________________________________
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>
>
>
> --
> Joel Goldstick
> _______________________________________________
> Tutor maillist - Tutor@python.org
> To unsubscribe or change subscription options:
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I was able to get it working like this...
password = "foobar"
attempt = 0
while (password != "unicorn") and (attempt <= 3):
password = input("Password: ")
attempt = attempt + 1
if attempt == 3:
print ("That must have been complicated..")
break
if (password == "unicorn"):
print ("Welcome in..")
Not sure if it helps.
- Paul
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