I have a 1960 17' Uniflite runabout with a 50HP outboard. It's perfect for the boat. One thing I suggest you check is the transom for dryrot; it is a common problem with these boats. The way to do it is to take an awl and try to shove in several place on the inside of the transom, especially along the bottom. If it has dryrot, don't despair, it can be fixed.
On Sep 19, 10:03 pm, "Jack's57" <[email protected]> wrote: > Thanks guys! according to Waterguy's link and example, I've come up > with about 55hp. > > I'll be selling my 85 and buying a reliable 50-60hp engine. Hopefully > I can get out before it gets too cold! > > -Jack > > On Sep 18, 4:36 pm, Bob S <[email protected]> wrote: > > > > > I'm impressed waterguy. You continually come up with the most > > impressive, in depth answers. You a boat builder/engineer/naval > > architect? > > > Where do you get this stuff? > > > Bob S. > > > On Sep 18, 2:46 pm, waterguy <[email protected]> wrote: > > > > Your answer is found at 33 CFR § 183.53. Here's a > > > link:http://ecfr.gpoaccess.gov/cgi/t/text/text-idx?c=ecfr&sid=01a07e768bf6... > > > > First, you compute a factor. This factor is [boat length] times > > > [transom width]. If the transom is not the widest part of the boat, > > > substitute the width measured at the widest part of the stern quarter. > > > > If your factor is less than 52.5, you apply the horsepower ratings > > > shown in the table in 33 CFR § 183.53. That table provides > > > Factor :: Horsepower > > > 0-35 :: 3 > > > 36-39 :: 5 > > > 40-42 :: 7.5 > > > 43-45 :: 10 > > > 46-52 :: 15 > > > > If the factor is greater than 52.5, you apply a formula to the > > > factor. There are 3 possible factors depending on transom height and > > > hull shape. Your boat is not flat bottomed with hard chines, and it > > > probably doesn't have a 20-inch transom (my guess would be 15"). So > > > the formula you apply is: 0.8 times [factor] minus 25. > > > > If the capacity calculated is not a multiple of 5, you may raise to > > > the next higher multiple of 5. > > > > So, if your boat is 14 feet long and is 6 feet wide at the transom, > > > your factor is 14 x 6 = 84 > > > Applying the formula, 0.8 x 84 = 67.2 > > > 67.2 - 25 = 42.2 > > > > Raised to nearest multiple of 5 = 45 hp capacity.- Hide quoted text - > > - Show quoted text - --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "UnifliteWorld" group. To post to this group, send email to [email protected] To unsubscribe from this group, send email to [email protected] For more options, visit this group at http://groups.google.com/group/unifliteworld?hl=en -~----------~----~----~----~------~----~------~--~---
