Ken Ray wrote:
On 2/28/06 3:57 PM, "Jonathan Lynch" <[EMAIL PROTECTED]> wrote:
I like the idea of using itemdel as a means of counting - very clever...
I was thinking there must be some other immediate means of counting?
How about this one?
function CountChars pString,pChar
replace space with null in pString
replace pChar with space in pString
return ((the number of words of pString)-1)
end CountChars
That doesn't work because a sequence of consecutive spaces doesn't cause
intermediate null words - the sequence is a single word delimiter. So if
you tried to count the ":"s in "asd:::fgh" you'd replace it to "asd
fgh" - which word-counting says is the same as "asd:fgh".
It would also get the wrong answer if there are quotes in the string
forming a quoted word. I think it requires a space immediately before
the first quote for ti to be considered the start of a quoted word - but
once it does form a quoted word, internal spaces are ignored, as is the
lack of a space after the second quote.
string word count
------- ----------
asdfgh 1 as you wanted
asd"extra"fgh 1 again
asd "extra"fgh 3 !!
asd "extra" fgh 3 again
asd "extra" fgh 3 again
--
Alex Tweedly http://www.tweedly.net
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