Sergio Bruder wrote:
>>> select id,username,extra,created,creator,sitegroup from person where lastname like
>'%bruder%';
>>>
>+----+----------+-----------------------------------+---------------------+---------+-----------+
>>> | id | username | extra | created |
>creator | sitegroup |
>>>
>+----+----------+-----------------------------------+---------------------+---------+-----------+
>>> | 1 | admin | Administrator account for Midgard | 0000-00-00 00:00:00 |
>0 | 0 |
>>> | 2 | bruder | | 2000-05-05 14:53:44 |
>1 | 0 |
>>>
>+----+----------+-----------------------------------+---------------------+---------+-----------+
>>>
>>User 'bruder' is not in SG1. I think that's the problem.
>
>
> But I compiled *without* sitegroup support and I'm using 1.2.5 admin
> site code. sitegroups now are the only option?
Absolutely not. I now see you said earlier you compiled without, but
since your samples seemed to imply SGs...
User 'bruder' should work. The -6 is a bit of a surprise in this regard.
If you have mysql logging turned on, I'd be most interested in what it
says. It should look like
SELECT id,password FROM person WHERE username="bruder"
I'd also be interested what this query returns if you type it into mysql
yourself.
Emile
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