I get "1234567890" (jena v 3.5.0)
sparql -v 'select ?substr where {BIND(substr("1234567890", 0, 11) AS
?substr)}'
1 SELECT ?substr
2 WHERE
3 { BIND(substr("1234567890", 0, 11) AS ?substr) }
----------------
| substr |
================
| "1234567890" |
----------------
I get this for versions back to 2.10.0.
Andy
On 06/11/17 14:22, Jerven Tjalling Bolleman wrote:
Dear Jena-Devs,
I believe that the following query
select ?substr where {BIND(substr("1234567890", 0, 11) AS ?substr)}
should return
| substr |
================
| "1234567890" |
instead of the current
| substr |
==========
| |
I take this from reading the spec here.
https://www.w3.org/TR/xpath-functions/#func-substring
If people agree with my reading I will be happy to submit a patch.
Regards,
Jerven
