On 06/11/17 15:13, Jerven Tjalling Bolleman wrote:
Of course to make it even stranger
sparql -v "select * where {BIND(substr(str("1234567890"), 0, 11) AS
?substr)}"
Does work as expected!
Because the expression is
substr(str(1234567890), 0, 11)
"1234567890" becomes integer 1234567890 due to the quoting. bash allows
quoting in the middle of arguments. Unlike some other OS shells, bash
evaluates quotes before passing to the command.
Andy
>> echo "ABC"DEF'GHI'
ABCDEFGHI
>>
Regards,
Jerven
1 SELECT ?substr
2 WHERE
3 { BIND(substr(str(1234567890), 0, 11) AS ?substr) }
16:13:39 INFO exec :: QUERY
SELECT ?substr
WHERE
{ BIND(substr(str(1234567890), 0, 11) AS ?substr) }
16:13:39 INFO exec :: ALGEBRA
(project (?substr)
(extend ((?substr "1234567890"))
(table unit)))
On 11/06/2017 03:45 PM, Jerven Tjalling Bolleman wrote:
Dear Andy,
That makes it very strange because this is what I get
$ sparql --version
Jena: VERSION: 3.4.0
Jena: BUILD_DATE: 2017-07-17T11:43:07+0000
ARQ: VERSION: 3.4.0
ARQ: BUILD_DATE: 2017-07-17T11:43:07+0000
RIOT: VERSION: 3.4.0
RIOT: BUILD_DATE: 2017-07-17T11:43:07+0000
$ sparql -v "select ?substr where {BIND(substr("1234567890", 0, 11) AS
?substr)}"
1 SELECT ?substr
2 WHERE
3 { BIND(substr(1234567890, 0, 11) AS ?substr) }
15:43:31 INFO exec :: QUERY
SELECT ?substr
WHERE
{ BIND(substr(1234567890, 0, 11) AS ?substr) }
15:43:31 INFO exec :: ALGEBRA
(project (?substr)
(extend ((?substr (substr 1234567890 0 11)))
(table unit)))
----------
| substr |
==========
| |
----------
Regards,
Jerven
On 11/06/2017 03:34 PM, Andy Seaborne wrote:
I get "1234567890" (jena v 3.5.0)
sparql -v 'select ?substr where {BIND(substr("1234567890", 0, 11) AS
?substr)}'
1 SELECT ?substr
2 WHERE
3 { BIND(substr("1234567890", 0, 11) AS ?substr) }
----------------
| substr |
================
| "1234567890" |
----------------
I get this for versions back to 2.10.0.
Andy
On 06/11/17 14:22, Jerven Tjalling Bolleman wrote:
Dear Jena-Devs,
I believe that the following query
select ?substr where {BIND(substr("1234567890", 0, 11) AS ?substr)}
should return
| substr |
================
| "1234567890" |
instead of the current
| substr |
==========
| |
I take this from reading the spec here.
https://www.w3.org/TR/xpath-functions/#func-substring
If people agree with my reading I will be happy to submit a patch.
Regards,
Jerven
